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EleoNora [17]
3 years ago
5

I need help on this!!!

Mathematics
2 answers:
Dafna1 [17]3 years ago
6 0

Answer:

There should be 13 if I’m right

Step-by-step explanation:

Oduvanchick [21]3 years ago
6 0

Answer:

42

Step-by-step explanation:

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True or false: In (r, theta), the value of r can be negative.
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The answer to the mathematics question presented above is 'True'. It is correct to say that in (r theta), the value of r can be negative. A negative radius can be used when it comes to graphing a "polar'' function. Thus, the answer to the question is 'true'. 
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P- 6= -5 what is the answer (NEED HELP)
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P=1

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5 0
3 years ago
An isosceles triangle has a perimeter of 33 cm. The unequal side has a length 3 cm more than the equal side. Find the length of
grigory [225]

Answer:

let equal side=x

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6 0
3 years ago
Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering p
tankabanditka [31]

Answer:

1.778 times more or 16/9 times more

Step-by-step explanation:

Given:

- Mirror 1: D_1 = 8''

- Mirror 2: D_2 = 6"

Find:

Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering power?

Solution:

- The light gathering power of a mirror (LGP) is proportional to the Area of the objects:

                                           LGP ∝ A

- Whereas, Area is proportional to the squared of the diameter i.e an area of a circle:

                                           A ∝ D^2

- Hence,                              LGP ∝ D^2

- Now compare the two diameters given:

                                           LGP_1 ∝ (D_1)^2

                                           LGP ∝ (D_2)^2

- Take a ratio of both:

                           LGP_1/LGP_2 ∝ (D_1)^2 / (D_2)^2

- Plug in the values:

                               LGP_1/LGP_2 ∝ (8)^2 / (6)^2

- Compute:             LGP_1/LGP_2 ∝ 16/9 ≅ 1.778 times more

6 0
3 years ago
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