A. Carbon dioxide is released during cellular respiration
45.6 mL of 0.0600 M of 
is added to 25.0 mL of HCl of unknown concentration then , the concentration of HCl is 0.032 M .
Calculation ,
Formula used : 
= 
...( 1 )
Where 
= concentration of = 0.0600 M ( given )
= concentration of HCl = ? ( to be find )
= volume of = 25.0 mL ( given )
= volume of HCl = 45.6 mL ( given )
Now , put the value of all volume and concentration in equation ( 1 ) we get .
0.0600 M × 25.0 mL = × 45.6 mL
= 0.0600 M × 25.0 mL / 45.6 mL = 0.032 M
Therefore , concentration of unknown concentration of HCl is 0.032 M .
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The energy release when dissolving 1 mol of NaOH in water is 445.1 kJ
the mass of NaOH to be dissolved is 32.0 g
The number of NaOH moles in 32.0 g - 32.0 g / 40 g/mol = 0.8 mol
the energy released whilst dissolving 1 mol of NaOH - 445.1 kJ
when dissolving 0.8 mol - the energy released is 445.1 kJ/mol x 0.8 mol
therefore heat released is - 356.08 kJ
answer is -356.08 kJ
Energy=mass x the speed of light squared.
