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Firlakuza [10]
3 years ago
5

76.0 mol of P4O10 contains how many moles of P?

Chemistry
2 answers:
NikAS [45]3 years ago
8 0
For a mole of P4O10, there are 4 moles of P. Hence for 76 moles of P4O10, the number of P moles is a total of 304. 
MAVERICK [17]3 years ago
6 0

Answer : The number of moles of phosphorous are 304 moles.

Explanation :

The formula of given compound is, P_4O_{10}

In P_4O_{10} compound, there 4 moles of phosphorus and 10 moles of oxygen.

As we are given that the moles of P_4O_{10} is 76.0 mole. Now we have to determine the number of moles of phosphorous (P).

As, 1 mole of P_4O_{10} has 4 moles of phosphorous

So, 76.0 mole of P_4O_{10} has 4\times 76.0=304moles of phosphorous

Therefore, the number of moles of phosphorous are 304 moles.

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Josh drives her scooter 7 km north. she stops for lunch and then drives 5 km east. what distance does she cover? what was her di
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Which of the following reactions show a decrease in entropy? a. CaO(s) + H2O(l) Ca(OH)2 (s)
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Type the correct answer in the box. Express your answer to three significant figures. Calcium nitrate reacts with sodium phospha
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6.07 grams is the theoretical yield of calcium phosphate (Ca₃(PO₄)₂).

<h3>How we calculate mass from moles?</h3>

Mass of any substance can be calculated by using moles as:

n = W/M, where

W = required mass

M= molar mass

Given chemical reaction is:

3Ca(NO₃)₂ + 2Na₃PO₄ → 6NaNO₃ + Ca₃(PO₄)₂

From the stoichiometry it is clear that:

3 moles of Ca(NO₃)₂ = produce 1 mole of Ca₃(PO₄)₂

Given mass of Ca(NO₃)₂ = 96.1g

Mole of Ca(NO₃)₂ = 96.1g/164g/mol = 0.5859moles

So, 0.5859 moles of Ca(NO₃)₂ = produce 0.5859×1/3 = 0.0196 moles of Ca₃(PO₄)₂

Required mass of Ca₃(PO₄)₂ will be calculated by using moles as:

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To know more about moles, visit the below link:

brainly.com/question/15373263

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