Answer:
The theoretical yield of lithium nitride is 7.52 g.
Explanation:
Moles of lithium =
Moles of nitrogen gas =
According to reaction, 6 moles of lithium reacts with 1 mole of nitrogen gas.
Then 0.6428 moles of lithium will react with:
of nitrogen gas
As we can see that moles of lithium are in limiting amount. So, the moles of lithium nitride will be depend upon the moles of lithium. Hence, lithium is a limiting reagent.
According to reaction,6 moles of lithium gives 2 moles of lithium nitride.
Then 0.6428 moles of lithium will give:
of lithium nitride
Mass of 0.21428 moles of lithium nitride:
0.2143 mol × 35 g/mol= 7.52 g
The description which accurately represents a water molecule is slightly negative oxygen pole, slightly positive hydrogen poles.
Water is a polar molecule. This means that the molecule has a dipole moment.
The polarity of water arises from the difference in electronegativity between hydrogen and oxygen.
Hence, in water molecule, oxygen is slightly negative and hydrogen is slightly positive thereby resulting in a dipole.
Learn more: brainly.com/question/10904296
<span>Dmitri Mendeleev's Periodic Law states that chemical and physical properties repeat themselves in groups of 8.</span>
Beryllium has 4 protons, 4 electrons and 5 neutrons
Answer:
The answer to your question is C₄H₅N₂O
Explanation:
Process
1.- Calculate the percent of oxygen in the sample
Percent of oxygen = 100 - 49.49 - 5.15 - 28.87
Percent of oxygen = 16.49 %
2.- Write the percents as grams
C = 49.49 g
H = 5.15 g
N = 28.87 g
O = 16.47 g
3.- Convert the grams to moles
C 12 g ------------------- 1 mol
49.49 g ---------------- x
x = (49.49 x 1) 12
x = 4.12 moles
H 1 g ------------------- 1 mol
5.15 g ---------------- x
x = (5.15 x 1)/ 1
x = 5.15 moles
N 14 g --------------- 1 mol
28.87 g ---------- x
x = (28.87 x 1) / 14
x = 2 mol
O 16 g ---------------- 1 mol
16.49 g ----------- x
x = (16.49 x 1) / 16
x = 1.03 moles
4.- Divide by the lowest number of moles
C 4.12 / 1.03 = 4
H 5.15 / 1.03 = 5
N 2 / 1.03 = 1.9 ≈ 2
O 1.03 / 1.03 = 1
5.- Write the empirical formula
C₄H₅N₂O
