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Slav-nsk [51]
3 years ago
10

What figure is shown in the drawing ? JH , JK , EJ , EK

Mathematics
1 answer:
Nat2105 [25]3 years ago
6 0

Answer:

I believe it is jk the figure?

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A standard deck of cards contains 52 cards. One card is selected from the deck.​(a)Compute the probability of randomly selecting
Aneli [31]

a. There are four 5s that can be drawn, and \binom43=4 ways of drawing any three of them. There are \binom{52}3=22,100 ways of drawing any three cards from the deck. So the probability of drawing three 5s is

\dfrac{\binom43}{\binom{52}3}=\dfrac4{22,100}=\dfrac1{5525}\approx0.00018

In case you're asked about the probability of drawing a 3 or a 5 (and NOT three 5s), then there are 8 possible cards (four each of 3 and 5) that interest you, with a probability of \frac8{52}=\frac2{13}\approx0.15 of getting drawn.

b. Similar to the second case considered in part (a), there are now 12 cards of interest with a probability \frac{12}{52}=\frac3{13}\approx0.23 of being drawn.

c. There are four 6s in the deck, and thirteen diamonds, one of which is a 6. That makes 4 + 13 - 1 = 16 cards of interest (subtract 1 because the 6 of diamonds is being double counted by the 4 and 13), hence a probability of \frac{16}{52}=\frac4{13}\approx0.31.

- - -

Note: \binom nk is the binomial coefficient,

\dbinom nk=\dfrac{n!}{k!(n-k)!}={}_nC_k=C(n,k)=n\text{ choose }k

6 0
4 years ago
For the last three months Olivia saved $75, $95, and $84. What is the minimum amount she should save next month in order to save
goblinko [34]
The answer is 106 dollars
8 0
3 years ago
Which statements is true
melamori03 [73]
All squares are rectangles
all squares are rhombuses

6 0
3 years ago
Read 2 more answers
Who knows the answer to the rest of this?
Angelina_Jolie [31]
I would help but am I gonna
4 0
3 years ago
At an amusement park , the cost of 3 adult tickets and 4 children’s ticket is $126.50 another customer paid $120.50 for 2 adult
KonstantinChe [14]

Answer:

1 Adult ticket=$21.50 ; 1 Children ticket=$15.50

Step-by-step explanation:

3A+4C=126.50

2A+5C=120.50

We find the price of adult tickets 1st.

15A+20C=632.5

8A+20C=482

7A=632.5-482=150.5

1A=21.50

Now we find Children ticket

6A+8C=253

6A+15C=361.50

7C=108.50

1C=15.50

4 0
4 years ago
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