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slega [8]
3 years ago
10

Using the Bohr model, determine the lowest possible energy, in joules, for the electron in the He+ ion.

Chemistry
1 answer:
lianna [129]3 years ago
8 0

Answer:

E=-8.72\times 10^{-18}\ Joules

Explanation:

The expression for Bohr energy of the hydrogen-like species is:

E_n=-Z^2\times \frac{2.179\times 10^{-18}}{n^2}\ Joules

Where, Z is the atomic number of the element

For, He^{2+}, Z = 2

For lowest energy, n = 1

Thus, Applying the values as:-

E=-2^2\times \frac{2.179\times 10^{-18}}{1^2}\ Joules

E=-8.72\times 10^{-18}\ Joules

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Answer: Double displacement reaction

Explanation:

Double displacement reaction is defined as the reaction where exchange of ions takes place.

The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

The chemical reaction between aqueous magnesium sulfate and aqueous sodium carbonate is represented as:

MgSO_4(aq)+Na_2CO_3(aq)\rightarrow Na_2SO_4(aq)+MgCO_3(s)

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State the number of neutrons in an atom of Ne-20 and the number of neutrons in an atom of Ne-22. choose two answers * 1 point Ne
saveliy_v [14]

Answer:

Ne 20: 10

and

Ne 22: 12

Explanation:

Ne-20:

N = A - Z = 20 - 10 = 10 neutrons

Ne-22:

N = A - Z = 22 - 10 = 12 neutrons

N: number of neutrons

A: mass number

Z: atomic number

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Which of the following should have the highest conductivity? a. 3.0 M NaCl b. 2.1 M Na3PO4 c. 2.4 M CaCl2 d. 3.2 M NH4NO3
Aleks [24]

Answer:

The correct answer is option b, that is, 2.1 M Na₃PO₄.

Explanation:

The solution with the largest concentration of ions will possess the highest conductivity.

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Here the total number of ions is 2, therefore, the concentration of ions is 3.0 × 2 = 6.0 M

b) 2.1 M Na₃PO₄

Na₃PO₄ ⇔ 3 Na⁺ + PO₄³⁻

Here the total number of ions i 4. Therefore, the concentration of ions is

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c) 2.4 M CaCl₂

CaCl₂ ⇔ Ca²⁺ + 2Cl⁻

The total number of ions is 3. Therefore, the concentration of ions is

2.4 × 3 = 7.2 M

d) 3.2 M NH₄NO₃

NH₄NO₃ ⇔ NH₄⁺ + NO₃⁻

The total number of ions is 2. The concentration of ions will be,

3.2 × 2 = 6.4 M

Hence, the highest conductivity will be of 2.1 M Na₃PO₄.

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