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Fantom [35]
3 years ago
8

Metallic or nonmetallic elements or compounds of elements that occur naturally in earth's crust are

Chemistry
1 answer:
jek_recluse [69]3 years ago
3 0
I dont get it please help
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In order to wash out the impurity, you looked up some sketchy method from 1952 which Hank Pym wrote during his Ph. D. under E. J
Eva8 [605]

Answer:

516.24

Explanation:

The solved solution is in the attached document.

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3 years ago
Mengapa air panas maupun air dingin yang disimpan di dalam termos cenderung lebih tahan lama suhu panas atau dinginnya
Zarrin [17]
Yes yes yes yes yes yes yes yes yes yes
5 0
4 years ago
Which of the following is a correct formula unit? PbCl AlP Li3Al ClO
zavuch27 [327]

Answer:  AIP  

There are two types of substances mixture and pure substance. Mixture has NO chemical formula and a pure substance has a chemical formula. There are two types of pure substances, elements (mono atomic and molecular) and compounds ( covalent and ionic).  

Ionic compounds do not exist in independent molecular form. They form three dimensional crystal lattice, in which each ion is surrounded by oppositely charged ion.  so the ratio of ion is called the formula unit  


3 0
4 years ago
Read 2 more answers
Please help me with these?
Julli [10]

Question 5 is the second one.


8 0
3 years ago
How many moles of ScCl3 can be produced when 10.00 mol Sc react with 9.00 mol Cl2
Nuetrik [128]

Answer:

Moles of ScCl_3 = 6 moles

Explanation:

The reaction of Sc and Cl_2 to make ScCl_3 is:

2Sc+3Cl_2⇒2ScCl_3

The above reaction shows that 2 moles of Sc  can react with 3 moles of Cl_2 to form ScCl_3.

Mole Ratio= 2:3

For 10 moles of Sc we need:

Moles of Cl_2 = Moles of Sc *\frac{3 moles of Cl_2}{2 Moles of Sc}

Moles of Cl_2 = 10 *\frac{3 moles of Cl_2}{2 Moles of Sc}

Moles of Cl_2 =15 moles

So 15 moles of Cl_2 are required to react with 10 moles of Sc but we have 9 moles of Cl_2 , it means Cl_2 is limiting reactant.

Moles of ScCl_3=Given\  Moles\  of\ Cl_2 *\frac{2\  Moles\ o\ fScCl_3}{3\ Moles\ of\ Cl_2}

Moles\ of\  ScCl_3=9 *\frac{2\  Moles\ of\ ScCl_3}{3\ Moles\ of\ Cl_2}

Moles of ScCl_3= 6 moles

4 0
3 years ago
Read 2 more answers
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