D is wrong. It can't have 2 angles equal to or greater than 90.
2x + 116.6 = 180
2x = 180 - 116.6
2x = 63.4
x = 63.4/2
x = 31.7 Two of this size are the only possible answers.
I did this test b4, yours is answer #number 12
Convert things to their basic forms.
<span>Remember a few identities </span>
<span>sin^2 + cos^2 = 1 so </span>
<span>sin^2 = 1 - cos^2 and </span>
<span>cos^2 = 1 - sin^2 </span>
<span>I'm going to skip typing the theta symbol, just to make things faster. Just assume it is there and fill it in as you work the problems. </span>
<span>Follow along to see how each problem was worked out. You'll catch on to the general technique. </span>
<span>====== </span>
<span>1. sec θ sin θ </span>
<span>1/cos * sin = sin/cos = tan </span>
<span>2. cos θ tan θ </span>
<span>cos * sin/cos = sin </span>
<span>3. tan^2 θ- sec^2 θ </span>
<span>sin^2 / cos^2 - 1/cos^2 </span>
<span>(sin^2 - 1)/cos^2 </span>
<span>-(1-sin^2)/cos^2 </span>
<span>-cos^2/cos^2 </span>
<span>-1 </span>
<span>4. 1- cos^2θ </span>
<span>sin^2 </span>
<span>5. (1-cosθ)(1+cosθ) </span>
<span>Remember (a+b)(a--b) = a^2 - b^2 </span>
<span>1-cos^2 = sin^2 </span>
<span>6. (secx-1) (secx+1) </span>
<span>sec^2 -1 </span>
<span>1/cos^2 - 1 </span>
<span>1/cos^2 - cos^2/cos^2 </span>
<span>(1-cos^2)/cos^2 </span>
<span>sin^2/cos62 </span>
<span>tan^2 </span>
<span>7. (1/sin^2A)-(1/tan^2A) </span>
<span>1/sin^2 - 1/(sin^2/cos^2) </span>
<span>1/sin^2 - cos^2/sin^2 </span>
<span>(1-cos^2)/sin^2 </span>
<span>sin^2/sin^2 </span>
<span>1 </span>
<span>8. 1- (sin^2θ/tan^2θ) </span>
<span>1-sin^2/(sin^2/cos^2) </span>
<span>1 - sin^2*cos^2/sin^2 </span>
<span>1-cos^2 </span>
<span>sin^2 </span>
<span>9. (1/cos^2θ)-(1/cot^2θ) </span>
<span>1/cos^2 - 1/(cos^2/sin^2) </span>
<span>1/cos^2 - sin^2/cos^2 </span>
<span>(1-sin^2)/cos^2 </span>
<span>cos^2/cos^2 </span>
<span>1 </span>
<span>10. cosθ (secθ-cosθ) </span>
<span>cos *(1/cos - cos) </span>
<span>1-cos^2 </span>
<span>sin^2 </span>
<span>11. cos^2A (sec^2A-1) </span>
<span>cos^2 * (1/cos^2 - 1) </span>
<span>1 - cos^2 </span>
<span>sin^2 </span>
<span>12. (1-cosx)(1+secx)(cosx) </span>
<span>(1-cos)(1+1/cos)cos </span>
<span>(1-cos)(cos + 1) </span>
<span>-(cos-1)(cos+1) </span>
<span>-(cos^2 - 1) </span>
<span>-(-sin^2) </span>
<span>sin^2 </span>
<span>13. (sinxcosx)/(1-cos^2x) </span>
<span>sin*cos/sin^2 </span>
<span>cos/sin </span>
<span>cot </span>
<span>14. (tan^2θ/secθ+1) +1 </span>
<span>(sin^2/cos^2)/(1/cos) + 2 </span>
<span>sin^2/cos + 2 </span>
<span>sin*tan + 2 </span>
Answer:
y = 9x + 5
With y in dollars and x in hours.
Step-by-step explanation:
Bike-a-Rama charges $9 hourly for each of their bikes. And they have a fixed maintenance fee of $5.
The total cost of renting a bike, just like almost every business venture, would be given as
Total Cost = (Fixed Cost) + (Variable Cost)
Total Cost = y (the total absolute cost of renting a bike)
Fixed Cost = The compulsory maintenance cost for everyone that wants to rent = $5
Variable Cost = (Rent Rate given per hour) × (number of hours the bike is rented)
Rent rate given per hour = $9 per hour
Number of hours the Nike is rented = x
Variable Cost = $9x
Total Cost = y = 5 + 9x
So, y = $(9x + 5)
Hope this Helps!!!
Answer:
1.5 kg of pepper cheddar cheese and 4.5 kg of Pennsylvania jack was used in the mixture.
Step-by-step explanation:
Pepper Cheddar cheese = $15 per kilogram
Pennsylvania jack = $11 per kilogram
The cheese sampler includes a Pepper Cheddar cheese and a Pennsylvania jack that cost $15 per kilogram and $11 per kilogram respectively.
The mixture = 6 kg
Let
a = kg of the pepper cheddar cheese
b = kg of the Pennsylvania jack
a + b = 6............(i)
Rate
15a + 11b/6 = 12
15a + 11b = 72.............(ii)
Combine the equation
a + b = 6............(i)
15a + 11b = 72.............(ii)
a = 6 - b
15(6 - b) + 11b = 72
90 - 15b + 11b = 72
90 - 72 = 15b - 11b
18 = 4b
divide both sides by 4
b = 18/4
b = 4.5 kg
insert the value of b in equation (i)
a + b = 6............(i)
a = 6 - 4.5
a = 1.5 kg
1.5 kg of pepper cheddar cheese and 4.5 kg of Pennsylvania jack was used in the mixture.
