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WITCHER [35]
3 years ago
7

I need help solving this chemistry question ​

Chemistry
1 answer:
Arturiano [62]3 years ago
3 0

Answer:

I think the answer is 22.2

Explanation: What i DID was adding 12.0 + 10.0 and than that gave me 22 the I had added the to 0.200 and that how i got 22.2. Sorry if i got is wrong. :(

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alexandr1967 [171]

Answer:

The products  of self-ionization of water are OH⁻ and H⁺.

Explanation:

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<em>H₂O → OH⁻ + H⁺. </em>

<em></em>

The ionic product for water (Kw) = [OH⁻][H⁺] = 10⁻¹⁴.

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3 years ago
Write a balanced half-reaction for the reduction of permanganate ion mno−4 to solid manganese dioxide mno2 in acidic aqueous sol
Svetlanka [38]

The half-reaction includes either the reduction or the oxidation reaction of the redox reactions. In acidic solution permanganate ion will react with hydrogen ion to yield manganese ion and water.

<h3>What are Redox reactions?</h3>

Redox or oxidation-reduction reactions are the chemical reactions in which the oxidation and the reduction of the chemical species occur simultaneously.

Permanganate (VII) ion is a strong oxidizing agent and gets easily reduced to manganese ion in presence of the hydrogen ion in an acidic solution.

The balanced half-reaction for reduction is shown as,

\rm MnO_{4}^{-} \; (aq)+ 8H^{+} \; (aq)+ 5e^{-} \rightarrow Mn^{2+} \; (aq)+ 4H_{2}O \; (l)

Learn more about reduction reactions here:

brainly.com/question/10084275

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