953.6 g of iron (III) oxide (Fe₂O₃)
Explanation:
We have the following chemical reaction:
2 Fe₂O₃ (s) + 3 C (s) → 4 Fe (s) + 3 CO₂ (g)
We calculate the number of moles of CO₂ by using the following formula:
pressure × volume = number of moles × gas constant × temperature
number of moles = (pressure × volume) / (gas constant × temperature)
number of moles of CO₂ = (2.1 × 100) / (0.082 × 300)
number of moles of CO₂ = 8.54 moles
Taking in account the chemical reaction we devise the following reasoning:
if 2 mole of Fe₂O₃ produces 3 mole of CO₂
then X moles of Fe₂O₃ produces 8.54 mole of CO₂
X = (2 × 8.54) / 3 = 5.69 moles of Fe₂O₃
number of moles = mass / molar weight
mass = number of moles × molar weight
mass of Fe₂O₃ = 5.69 × 160 = 953.6 g
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would be produced from the complete reaction of 25 mL of 0.833 mol/L 
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