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3 years ago

I need help solving this chemistry question

Chemistry

1 answer:

Arturiano [62]3 years ago

3 0

Answer:

I think the answer is 22.2

Explanation: What i DID was adding 12.0 + 10.0 and than that gave me 22 the I had added the to 0.200 and that how i got 22.2. Sorry if i got is wrong. :(

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Each mineral group has a distinctive chemical feature such as

disa [49]

Answer:

Explanation:

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2 years ago

A 50/50 blend of engine coolant and water (by volume) is usually used in an automobile's engine cooling system. If a car's cooli

Diano4ka-milaya [45]

Answer:

$\large \boxed{109.17 \, ^{\circ}\text{C}}$

Explanation:

Data:

50/50 ethylene glycol (EG):water

V = 4.70 gal

ρ(EG) = 1.11 g/mL

ρ(water) = 0.988 g/mL

Calculations:

The formula for the boiling point elevation ΔTb is

$\Delta T_{b} = iK_{b}b$

i is the van’t Hoff factor — the number of moles of particles you get from 1 mol of solute. For EG, i = 1.

1. Moles of EG

$\rm n = 0.50 \times \text{4.70 gal} \times \dfrac{\text{3.785 L}}{\text{1 gal}} \times \dfrac{\text{1000 mL}}{\text{1 L}} \times \dfrac{\text{1.11 g}}{\text{1 mL}} \times \dfrac{\text{1 mol}}{\text{62.07 g}} = \text{159 mol}$

2. Kilograms of water

$m = 0.50 \times \text{4.70 gal} \times \dfrac{\text{3.785 L}}{\text{1 gal}} \times \dfrac{\text{998 g}}{\text{1 L}} \times \dfrac{\text{1 kg}}{\text{1000 g}} = \text{8.88 kg}$

3. Molal concentration of EG

$b = \dfrac{\text{159 mol}}{\text{8.88 kg}} = \text{17.9 mol/kg}$

4. Increase in boiling point

$\rm \Delta T_{b} = iK_{b}b = 1 \times 0.512 \, \, ^{\circ}\text{C} \cdot kg \cdot mol^{-1} \, \times 17.9 \cdot mol \cdot kg^{-1} = 9.17 \, ^{\circ}\text{C}$

5. Boiling point

$\rm T_{b} = T_{b}^{\circ} + \Delta T_{b} = 100.00 \, ^{\circ}\text{C} + 9.17 \, ^{\circ}\text{C} = \mathbf{109.17 \, ^{\circ}C}\\\rm \text{The boiling point of the solution is $\large \boxed{\mathbf{109.17 \, ^{\circ}C}}$}$

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3 years ago

What is the coefficient for hydrogen in the balanced equation for the reaction of solid molybdenum(iv) oxide with gaseous hydrog

anastassius [24]

The coefficient for hydrogen in the balanced equation of solid molybdenum(iV) oxide with gaseous hydrogen is 2

Explanation

Coefficient is defined to as a number in front of a chemical formula in a balanced chemical equation.

The reaction of molybdenum (iv) oxide with gaseous hydrogen is as below,

MoO2 + 2 H2→ Mo +2 H2O

From balanced equation above the coefficient for H2 is 2 since the number in front of H2 is 2

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3 years ago

1. What organisms keeps the ecosystem going but you can't see them with the naked eye?

jok3333 [9.3K]

Answer:

The answer is bacteria (microorganisms)

Explanation:

Bacteria can't be seen with the naked eye but it's part of a species that make up the biodiversity.

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3 years ago

A diagram is a:

Nimfa-mama [501]

Answer: A) A Visual representation of Information

Explanation:

Look up the definition of a diagram, it usually defines as what you would think. Example: If I drew a person and I wanted to represent who they were, that would be a diagram

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3 years ago

I need help solving this chemistry question ​

I need help solving this chemistry question