Answer:
C₅H₁₀O₄
Explanation:
The empirical formula is the simplest whole-number ratio of atoms in a compound.
The ratio of atoms is the same as the ratio of moles.
So, our job is to calculate the molar ratio of C:H:O.
Assume 100 g of deoxyribose.
1. Calculate the mass of each element.
Then we have 44.8 g C, 7.5 g H, and 47.7 g O.
2. Calculate the moles of each element

3. Calculate the molar ratio of the elements
Divide each number by the smallest number of moles
C:H:O = 3.730:7.44:2.981 = 1.251:2.50:1 = 5.005:9.98:4 ≈ 5:10:4
4. Write the empirical formula
EF = C₅H₁₀O₄
Answer:
The resulting pressure is 2.81 atm
Explanation:
According to Dalton's Law of Partial Pressure, each of the gases (A and B) will exert their pressure independently. If we use Boyle's Law to calculate the pressure of each of the gases separately we have:
Pressure of gas A:
p1V1 = p2V2
p1 = 2.4 atm
V1 = 722 mL
V2 = 722 + 169 = 891 mL
p2 =?
Clearing p2:
p2 = (p1V1)/V2 = (2.4*722)/891 = 1.94 atm
Pressure of gas B:
p1 = 4.6 atm
V1 = 169 mL
V2 = 169+722 = 891 mL
p2=?
Clearing p:
p2 = (4.6*169)/891 = 0.87 atm
Dalton's expression for total partial pressures is equal to:
ptotal = pA + pB = 1.94+0.87 = 2.81 atm
Chemicals dissolved in water. Calcite is a good example, if I'm not mistaken.
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Explanation: