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Vedmedyk [2.9K]

3 years ago

9

5) Calculate the volume, in liters, of 3.24 x 1022 molecules CI2

1 answer:

azamat3 years ago

5 0

Answer: 1.12 Liters

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given molecules}}{\text {avogadro's number}}=\frac{3.24\times 10^{22}}{6.023\times 10^{23}}=0.05moles$

1 mol of $Cl_2$ occupy = 22.4 L

Thus 0.05 mol of $Cl_2$ will occupy = $\frac{22.4}{1}\times 0.05=1.12 L$

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If a dog has a mass of 21.5 kg, what is its mass in the following units? Use scientific notation in all of your answers.

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2 years ago

[24 points] A sample of soil has a total volume of 205 cm3. The soil mass when saturated is 361 g. A specific yield test was con

telo118 [61]

Answer:

Follows are the solution to the given question:

Explanation:

Dry Soil weight = solid soil weight = $284 \ grams$

solid soil volume = $205 \ cc$

saturated mass soil = $361 \ g$

The weight of the soil after drainage is = $295 \ g$

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Water volume required for soil saturation = $\frac{77}{1} = 77 \ cc$

Sample volume of water: $= \frac{\text{water density}}{\text{water density input}}$

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$= 295 - 284 \\\\ = 11 \ cc.$

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$= \frac{77}{(205 + 77)} \\\\= \frac{77}{(282)} \\\\ = 27.30 \%$

(Its saturated water volume is equal to the volume of voids)

$\text{YIELD SPECIFIC} = \frac{\text{Soil water volume}}{\text{Soil volume total}}$

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3 years ago

Hardness in groundwater is due to the presence of metal ions, primarily Mg2 and Ca2 . Hardness is generally reported as ppm CaCO

Maslowich

Answer:

0.0144 M

1440 ppm

Explanation:

Ca(In)²⁺ + EDTA → Ca(EDTA)²⁺ + In

We use the volume of EDTA consumed in the titration to <u>calculate the moles of Ca⁺² ions</u>:

0.012 L * 0.0600 M * $\frac{1molCa^{+2}}{1molEDTA}$ = 7.20x10⁻⁴ mol Ca⁺²

Now we <u>calculate the molarity</u>:

7.20x10⁻⁴ mol Ca⁺² / 0.050 L = 0.0144 M

To calculate in ppm, we <u>use the moles of Ca⁺² and convert to mg of CaCO₃:</u>

7.20x10⁻⁴ mol Ca⁺² = 7.20x10⁻⁴ mol CaCO₃

7.20x10⁻⁴ mol CaCO₃ * 100g/mol * $\frac{1000mg}{1g}$ = 72 mg CaCO₃

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5 0

2 years ago

PLEASE HELPPPP???!!!!!!

sertanlavr [38]

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3 years ago