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Vedmedyk [2.9K]
3 years ago
9

5) Calculate the volume, in liters, of 3.24 x 1022 molecules CI2

Chemistry
1 answer:
azamat3 years ago
5 0

Answer: 1.12 Liters

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given molecules}}{\text {avogadro's number}}=\frac{3.24\times 10^{22}}{6.023\times 10^{23}}=0.05moles

1 mol of Cl_2 occupy = 22.4 L

Thus 0.05 mol of Cl_2 will occupy = \frac{22.4}{1}\times 0.05=1.12 L

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valentinak56 [21]

ans is A +BC → AC+ B

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6 0
4 years ago
A 0.529-g sample of gas occupies 125 ml at 60. cm of hg and 25°c. what is the molar mass of the gas?
Llana [10]

<span>Let's </span>assume that the gas has ideal gas behavior. <span>
Then we can use ideal gas formula,
PV = nRT<span>

</span><span>Where, P is the pressure of the gas (Pa), V is the volume of the gas (m³), n is the number of moles of gas (mol), R is the universal gas constant ( 8.314 J mol</span></span>⁻¹ K⁻¹) and T is temperature in Kelvin.<span>
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</span>P = 60 cm Hg = 79993.4 Pa
V = </span>125  mL = 125 x 10⁻⁶ m³

n = ?

<span> R = 8.314 J mol</span>⁻¹ K⁻¹<span>
T = 25 °C = 298 K
<span>
By substitution,
</span></span>79993.4 Pa<span> x </span>125 x 10⁻⁶ m³ = n x 8.314 J mol⁻¹ K⁻¹ x 298 K<span>
                                          n = 4.0359 x 10</span>⁻³ mol

<span>
Hence, moles of the gas</span> = 4.0359 x 10⁻³ mol<span>

Moles = mass / molar mass

</span>Mass of the gas  = 0.529 g 

<span>Molar mass of the gas</span> = mass / number of moles<span>
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Hence, the molar mass of the given gas is </span>131.07 g mol⁻¹

4 0
3 years ago
The quantity of antimony in a sample can be determined by an oxidation-reduction titration with an oxidizing agent. A 6.33-g sam
daser333 [38]

Answer:

Explanation:

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BrO3- (aq) → Br^3- (aq

to balance it water must be added to the right side and H⁺ be added to the left side

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multiply the second equation by 4

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add the two equation together and cancel the 8 e electrons on both side

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from the balanced equation of reaction;

one mole of BrO₃⁻  requires 4 moles of Sb³⁺

0.003588 moles of BrO₃⁻  will require = 0.003588 × 4 = 0.0144 moles of Sb³⁺

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b ) percentage of antimony in the ore = 1.748 g / 6.33 g = 27.62 %

4 0
3 years ago
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