The plant makes 3.50 × 10⁷ bearings per day
<em>Pounds of bearings</em> = 1 da × (4355 lb bearings/5 da) = 871.0 lb bearings
<em>Grams of bearings</em> = 871.0 lb bearings × (453.6 g bearings/1 lb bearings)
= 3.951 × 10⁵ g bearings
<em>No. of bearings</em> = 3.951 × 10⁵ g bearings × (1 bearing/0.0113 g bearing)
= 3.50 × 10⁷ bearings
Examples of Secondary Pollutants
Smog and acid rain are produced through similar sources, primarily vehicle and industry emissions. Though both result from human-caused air pollutants, there are chemical distinctions between the two.
hope it helps....!!!
Use the formula
E=mc^2
plug the values,
The amount of mass in kilograms would be lost is 8.71 x 10^-10
It would be, Sugar in water
Answer:
A. maintain electrical neutrality in the half-cells via migration of ions
Explanation:
Salt bridge -
For an electrochemical reaction , involving an anode and a cathode , both the electrodes are connect via a salt bridge to complete the circuit for the reaction .
One of the very important use of a salt bridge is to maintain the electrical neutrality of the respective half cells , which is achieved by the movement of ions .
Hence , from the given options , the correct option is ( a ) .
