Question

What is the approximate mass of 25 cm3 of silver, if the density is 10.5 g/cm3?

Answer 1

Answer:

Mass, m = 260 grams

Explanation:

It is given that,

Density of silver, $d=10.5\ g/cm^3$

Volume of the silver, $V=25\ cm^3$

We need to find the mass of a piece of silver. The formula for the density is given by :

$d=\dfrac{m}{V}$

$m=d\times V$

$m=10.5\ g/cm^3\times 25\ cm^3$

m = 262.5 g

or

m = 260 grams

So, the mass of the piece of the silver is 260 grams. Hence, this is the required solution.

Answer 2

25 x 10.5 = 262.5

So the approx. is 260 g which is answer D.