What is the approximate mass of 25 cm3 of silver, if the density is 10.5 g/cm3?

Chemistry

2 answers:

Ainat [17]2 years ago

7 0

Answer:

Mass, m = 260 grams

Explanation:

It is given that,

Density of silver, $d=10.5\ g/cm^3$

Volume of the silver, $V=25\ cm^3$

We need to find the mass of a piece of silver. The formula for the density is given by :

$d=\dfrac{m}{V}$

$m=d\times V$

$m=10.5\ g/cm^3\times 25\ cm^3$

m = 262.5 g

m = 260 grams

So, the mass of the piece of the silver is 260 grams. Hence, this is the required solution.

Lunna [17]2 years ago

6 0

25 x 10.5 = 262.5

So the approx. is 260 g which is answer D.

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