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Olenka [21]
3 years ago
11

What is the approximate mass of 25 cm3 of silver, if the density is 10.5 g/cm3?

Chemistry
2 answers:
Ainat [17]3 years ago
7 0

Answer:

Mass, m = 260 grams

Explanation:

It is given that,

Density of silver, d=10.5\ g/cm^3

Volume of the silver, V=25\ cm^3

We need to find the mass of a piece of silver. The formula for the density is given by :

d=\dfrac{m}{V}

m=d\times V

m=10.5\ g/cm^3\times 25\ cm^3

m = 262.5 g

or

m = 260 grams

So, the mass of the piece of the silver is 260 grams. Hence, this is the required solution.

Lunna [17]3 years ago
6 0
25 x 10.5 = 262.5

So the approx. is 260 g which is answer D.
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