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vagabundo [1.1K]
2 years ago
8

write the names of the following compounds. 1) iron + sulphur . 2) manganese + oxygen. aluminium + sulphur​

Chemistry
2 answers:
Vlada [557]2 years ago
8 0

Answer:

  1. FeS
  2. MnO₂
  3. Al₂S₃

Explanation:

<u>1) Iron + Sulphur = ?</u>

→ Iron sulfide

<u>2) Manganese + Oxygen = ?</u>

→ Manganese dioxide

<u>3) Aluminium + Sulphur = ?</u>

→ Aluminium sulfide

Tatiana [17]2 years ago
3 0

#1

  • Ferrous shows variable valency as it's transitive metal.

#For valency=2

\\ \rm\Rrightarrow {Fe(II)\atop Iron}+{S\atop Sulphur}\longrightarrow {FeS\atop Pyrrhotite}

#For valency=3

\\ \rm\Rrightarrow {Fe(III)\atop Iron}+{S\atop Sulphur}\longrightarrow {Fe_2O_3\atop Sesquisulfide}

#2

  • Manganese also shows variable valency

#For valency=2

\\ \rm\Rrightarrow {Mn(II)\atop Manganese}+{O_2\atop Oxygen}\longrightarrow {MnO_2\atop Manganese (II) Oxide}

#For valency=4

\\ \rm\Rrightarrow {Mn(IV)\atop Manganese}+{O_2\atop Oxygen}\longrightarrow {MnO_4\atop Permanganate}

#3

\\ \rm\Rrightarrow {Al\atop Aluminium}+{S\atop Sulphur}\longrightarrow {Al_2S_3\atop Aluminium\:Sulphide}

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The sp of pbbr2 is 6. 60×10−6. what is the molar solubility of pbbr2 in pure water?
Inessa05 [86]

Ksp of PbBr₂ is 6.60 × 10⁻⁶. The molar solubility of PbBr₂ in pure water is 0.0118M.

Ksp or Solubility Product Constant is an equilibrium constant for the dissociation in an aqueous solution.

Molar solubility (S) is the concentration of the dissolved substance in a solution that is saturated.

Let the molar solubility be S upon dissociation.

PbBr₂ or Lead Bromide dissociates in pure water as follows:

                          PbBr₂ ----------> Pb⁺² + Br⁻

                                                     S      2S

Ksp = [Pb⁺²] [ Br⁻]

Ksp = (S) (2S)²

Ksp = 4S³

6.60 × 10⁻⁶ = 4S³

S = 0.0118M

Hence, the Molar solubility S is 0.0118M.

Learn more about Molar solubility here, brainly.com/question/16243859

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6 0
1 year ago
Which type of carbon fixation stores carbon dioxide in acid form? a. c3 b. c4 c. cam d. all of the above
Luba_88 [7]

The type of carbon fixation stores carbon dioxide in acid form is CAM i.e. crassulacean acid metabolism.

<h3>What are CAM?</h3>

CAM stands for crassulacean acid metabolism in this process photosynsthesis is occured at day time but the exchange of gases takes place at night itself only.

In this carbon fixation process, carbon dioxide is stored in the form of organic acid malic acid and losses carbon dioxide at the night time and by doing this it helps in the storage of water.

Hence option (C) is correct.

To know more about CAM, visit the below link:

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8 0
2 years ago
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The activation energy of a reaction is 56.9 kj/mol and the frequency factor is 1.5×1011/s. Part a calculate the rate constant of
Vanyuwa [196]

We will use Arrehenius equation

lnK = lnA  -( Ea / RT)

R = gas constant = 8.314 J / mol K

T = temperature = 25 C = 298 K

A = frequency factor

ln A = ln (1.5×10 ^11) = 25.73

Ea = activation energy = 56.9 kj/mol = 56900 J / mol

lnK = 25.73 - (56900 / 8.314 X 298) = 2.76

Taking antilog

K = 15.8



5 0
3 years ago
Differentiate between Acidic radical and basic radical ​
Paladinen [302]

Explanation:

<em>Acidic</em><em> </em><em>radical</em><em> </em>

<em>Acid radical is the ion formed after the removal of Hydrogen ion (H+) from an acid. Example: When H2SO4 loses H+ ion, it forms HSO4− which is an acid radical.</em><em> </em>

<em>Basic</em><em> </em><em>radical</em><em> </em>

<em> The ion formed after the removal of hydroxide ion (OH−) from a base is known as basic radical.</em>

3 0
3 years ago
WILL MARK BRANILEST
ahrayia [7]

Answer:

FeCl3 is the limiting reactant

O2 is in excess

Theoretical yield Cl2 = 9.84 grams

The % yield is 96.5 %

Explanation:

Step 1: Data given

Mass of FeCl3 = 15.0 grams

Moles O2 = 4.0 moles

Mass of Cl2 produced = 9.5 grams

Step 2: The balanced equation

4FeCl3 + 3O2 → 2Fe2O3 + 6Cl2

Step 3: Calculate moles FeCl3

Moles FeCl3 = mass FeCl3 / molar mass FeCl3

Moles FeCl3 = 15.0 grams / 162.2 g/mol

Moles FeCl3 = 0.0925 moles

Step 4: Calculate limiting reactant

FeCl3 is the limiting reactant. Because we have way more (more than ratio 3:4) moles O2 than FeCl3. It will completely be consumed (0.0925 moles). O2 is in excess. There will react = 0.069375 moles O2

There will remain 4.0 - 0.069375 = 3.930625 moles

Step 5: Calculate moles Cl2

For 4 moles FeCl3 we need 3 moles O2 to produce 2 moles Fe2O3 and 6 moles Cl2

For 0.0925 moles FeCl3 moles we'll have 6/4 * 0.0925 = 0.13875 moles Cl2.

Step 6: Calculate mass Cl2

Mass Cl2 = moles * molar mass

Mass Cl2 = 0.13875 moles * 70.9 g/mol

Mass Cl2 = 9.84 grams

Step 7: Calculate % yield

% yield = (actual yield / theoretical yield) * 100%

% yield = (9.5 grams / 9.84 grams ) * 100%

% yield = 96.5 %

The % yield is 96.5 %

4 0
3 years ago
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