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DiKsa [7]
3 years ago
10

5. The heat of fusion of lead is 25 J/g and its melting point is 601 K. How much heat is given off as 3.0 g

Chemistry
1 answer:
PIT_PIT [208]3 years ago
5 0

Answer:

the heat given off is 75 J.

Explanation:

Given;

latent heat of fusion of lead, L= 25 J/g

mass of liquid lead, m = 3.0g

The heat given off is calculated as;

H = Lm

Where;

H is the quantity of heat given off

H = 25 x 3

H = 75 J.

Therefore, the heat given off is 75 J.

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Which of the following reactions results in a decrease in entropy? 2SO2 (g) + O2 (g) yields 2SO3 (g) 2NH3 (g) yields N2 (g) + 3H
Marrrta [24]
2SO2 (g) + O2 (g) yields 2SO3 (g)
3 0
3 years ago
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Solid iron is mixed with a solution of copper (I) nitrate to form iron (III) nitrate solution and metal copper. (what is the equ
DedPeter [7]

Answer:

Fe + 3CuNO₃ → Fe(NO₃)₃ + 3Cu

Explanation:

  • Solid Iron = Fe
  • Copper (I) nitrate = CuNO₃ (Nitrate, NO₃⁻, always has a charge of -1).
  • Iron (III) nitrate = Fe(NO₃)₃ (That way the compound has an overall neutral charge)
  • Metal Copper = Cu

Writing the equation using symbols leaves us with:

  • Fe + CuNO₃ → Fe(NO₃)₃ + Cu

<em>It is not balanced yet</em>. Now we <u>balance the NO₃ species on the left side</u>:

  • Fe + 3CuNO₃ → Fe(NO₃)₃ + Cu

Finally we<u> balance the Cu species on the right side</u>:

  • Fe + 3CuNO₃ → Fe(NO₃)₃ + 3Cu
5 0
2 years ago
How many moles of water in 100 grams
Bond [772]

Answer:

There are approximately 5.55 moles

Explanation:

6 0
2 years ago
A sample of gas with an initial volume of 28.4 Liters at a pressure of 725 mmHg and a temperature of 305 K is compressed to a vo
Lerok [7]

Answer:

The final pressure is 2.25 atm or 1710 mm Hg

Explanation:

Step 1: Data given

The initial volume = 28.4 L

The initial pressure = 725 mm Hg ( = 725/760 atm) = 0.953947 atm

The initial temperature = 305 K

The new volume is 14.8 L

The new temperature = 375 K

Step 2: Calculate the new pressure

(P1*V1)/T1 = (P2*V2)/T2

⇒ with P1 = the initial pressure = 725 mmHg = 0.953947 atm

⇒ with V1 = the initial volume = 28.4 L

⇒ with T1  = The initial temperature = 305 K

⇒ with P2 = the new pressure = TO BE DETERMINED

⇒ with V2 = the new volume = 14.8 L

⇒ with T2 = the new temperature = 375 K

(0.953947 * 28.4)/305 = (P2 * 14.8)/375

P2 = 2.25 atm = 1710 mm Hg

The final pressure is 2.25 atm or 1710 mm Hg

6 0
3 years ago
2) 183 cg =<br> kg<br> 5<br> .00183 kg<br> 0.0183 kg<br> .183 kg<br> 3) 0.25 kg =<br> g
OlgaM077 [116]

Answer:

183 cg = 0.00183 kg

0.25 kg = 250 g

Explanation:

Use conversion factors. 1kg is equal to 1 x 10^5 cg (100000) and 1 kg is equal to 1 x 10^3 grams (1000 grams).

5 0
3 years ago
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