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3 years ago

How do you calculate the mass of an element in a compound using percent composition?

Chemistry

1 answer:

Dmitry_Shevchenko [17]3 years ago

7 0

Answer:

Find the molar mass of all the elements in the compound in grams per mole.

Find the molecular mass of the entire compound.

Divide the component's molar mass by the entire molecular mass.

You will now have a number between 0 and 1. Multiply it by 100% to get percent composition.

Explanation:

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The compound gallium phosphide () is a compound semiconductor having mixed ionic and covalent bonding. The electronegativities f

9966 [12]

Answer:

$0.08875$

Explanation:

Hello,

In this case, the first step is to compute the difference in the electronegativity for the formed bond between gallium and phosphorous by:

$\Delta E=2.1-1.6\\\\\Delta E=0.5$

Thus, we can compute the percentage of ionic character by:

$\%\ ionic\ character=16\Delta E +3.5 (\Delta E)^2\\\\\%\ ionic\ character=16*0.5+3.5*0.5^2\\\\\%\ ionic\ character=8.875\%$

So the fraction is just:

$\frac{8.875}{100}=0.08875$

Which has sense since gallium phosphide is a non-polar compound.

Regards.

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3 years ago

What is the volume of 0.5 moles of a gas at 2 atmospheres of pressure and 15°c

liq [111]

Answer:

Explanation: convert temperature to kelvin by adding 273 and then input the values into the formula with the given constant

2*v=0.5*0.8206*288 then divide both sides by 2 and get the amount in litres which is 6

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3 years ago

Can someone help me asap

Kobotan [32]

answer:

explanation:

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and water is H2O

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3 years ago

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Mashutka [201]

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2 years ago

An 18 liter container holds 16.00 grams of oxygen gas (o2 at 45 °c. what is the pressure in the container?

Scrat [10]

Hello!

The pressure of an 18 L container which holds 16,00 grams of oxygen gas (O₂) at 45 °C is 0,725 atm

To solve this problem we first need to set up the data in the appropriate units to input it in the Ideal Gas Law.

a) 16 g of Oxygen gas to moles of oxygen gas:

$16gO_2* \frac{1 mol O_2}{32gO_2}=0,5 mol O_2$

b) 45 °C to K

$K=$^{\circ}$C + 273,15 = 45 $^{\circ}$C + 273.15=318,15 K$

Now, we clear the Ideal Gas Equation for P, and solve it:

$P*V=n*R*T \\ \\ P= \frac{n*R*T}{V}= \frac{(0,5mol)*(0,082 \frac{L*atm}{mol*K})* (318,15 K)}{18 L}= 0,725 atm$

Have a nice day!

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3 years ago