1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
9966 [12]
2 years ago
8

How do you calculate the mass of an element in a compound using percent composition?

Chemistry
1 answer:
Dmitry_Shevchenko [17]2 years ago
7 0

Answer:

Find the molar mass of all the elements in the compound in grams per mole.

Find the molecular mass of the entire compound.

Divide the component's molar mass by the entire molecular mass.

You will now have a number between 0 and 1. Multiply it by 100% to get percent composition.

Explanation:

You might be interested in
Why are the alkali metals and the halogens very reactive
jeyben [28]

Answer:

Answer in explanation

Explanation:

The reactivity or passiveness of an element depends solely on how close it is to attain a noble gas configuration. This means the closer an element is to attain a noble gas configuration, the greater its reactivity in both direction, positively or negatively.

Alkali metals belong to group 1 of the periodic table while halogens belong to group 17 of the periodic table. This means they are just one electron away from achieving the stability of a noble gas configuration. While alkali metals need to lose one electron to form a univalent positive ion, halogens news to gain one electron to form a univalent negative ion.

They tend to go about this vigorously and as such undergo several chemical reactions because of that single electron they neeed.

4 0
2 years ago
A compound distributes between benzene (solvent 1) and water (solvent 2) with a distribution coefficient, K = 2.7. If 1.0g of th
mote1985 [20]

Explanation:

The given data is as follows.

Solvent 1 = benzene,          Solvent 2 = water

 K_{p} = 2.7,         V_{S_{2}} = 100 mL

V_{S_{1}} = 10 mL,       weight of compound = 1 g

       Extract = 3

Therefore, calculate the fraction remaining as follows.

                  f_{n} = [1 + K_{p}(\frac{V_{S_{2}}}{V_{S_{1}}})]^{-n}

                                  = [1 + 2.7(\frac{100}{10})]^{-3}

                                  = (28)^{-3}

                                  = 4.55 \times 10^{-5}

Hence, weight of compound to be extracted = weight of compound - fraction remaining

                                  = 1 - 4.55 \times 10^{-5}

                                  = 0.00001

or,                               = 1 \times 10^{-5}

Thus, we can conclude that weight of compound that could be extracted is 1 \times 10^{-5}.

7 0
2 years ago
Read 2 more answers
A student needs exactly 1 gram of baking powder to conduct an experiment. The balance reads 0.37 grams. How
sammy [17]

Answer:

B

Explanation:

If the student needs one gram but so far only has 0.37 grams, then the amount they need is the difference between what they need and how much they already have. 1-0.37=0.63 grams.

...which isn't actually an option because none of them have decimal points but I would say it is B anyway because it is the equivalent ratio and maybe there was a typo.

Hope this helped!

6 0
3 years ago
Read 2 more answers
Air pressure is lowest in the lungs during whi h of the following points during inspiration or expiration
AlladinOne [14]

Answer:

Inspiration

Explanation:

This question is on application of Boyle's law; <u>pressure is inversely proportional to volume</u>.when we inhale air, the diaphragm and the muscles in the ribs contract thus increasing the volume in the lungs.Increased volume of the lungs cause the pressure to decrease.During exhaling, the diaphragm and muscles in the ribs relax, making the lungs to recoil and reduce in volume to force air out.Pressure in the lungs is increased than that in the environment making air to move out.

4 0
2 years ago
Consider a pot of water at 100 C. If it took 1,048,815 J of energy to vaporize the water and heat it to 135 C, how many grams of
jeka57 [31]

Answer:

There was 450.068g of water in the pot.

Explanation:

Latent heat of vaporisation = 2260 kJ/kg = 2260 J/g = L

Specific Heat of Steam = 2.010 kJ/kg C = 2.010 J/g = s

Let m = x g be the weight of water in the pot.

Energy required to vaporise water = mL = 2260x

Energy required to raise the temperature of water from 100 C to 135 C = msΔT = 70.35x

Total energy required = 2260x+x\times2.010\times(135-100)=2260x+70.35x=2330.35x

2330.35x=1048815\\x=450.068g

Hence, there was 450.068g of water in the pot.

8 0
2 years ago
Other questions:
  • Ann believes that carbohydrates store more energy than lipids. Nicco believes that lipids store twice as much energy as carbohyd
    8·2 answers
  • What is the rate for the second order reaction Products when [A] = 0.371 M? (k = 0.761 M's")​
    9·1 answer
  • What is the electron configuration of an element with atomic number 15 ? Please help
    11·2 answers
  • How do you balance S8+F2=SF6
    9·1 answer
  • What best describes the battery in this picture? an electrolytic cell that has spontaneous half reactions
    6·2 answers
  • Zn(s)+2HCl(aq)-&gt;ZnCl2(aq)+H2(g)
    5·2 answers
  • imagine yourself to be a cloth or plastic product manufacturer and prepare a 'flyer/add' as "my fabric /product is the best pls
    15·1 answer
  • Hhhhhhhhhhhheeeeeeeeeeeellllllllllllllllllpppppppppppppppp
    10·2 answers
  • Which type of reaction is <br> NaOH + KNO3 NaNO3 + KOH<br> --&gt;&gt;
    9·1 answer
  • Which statement best describes the movement of energy?.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!