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just olya [345]
3 years ago
6

X = 8 x = 9 x = 14 x = 15

Mathematics
1 answer:
jek_recluse [69]3 years ago
7 0

Answer:

x = 8

Step-by-step explanation:

The angles 75° and (5x + 35)° are vertical angles and congruent, thus

5x + 35 = 75 ( subtract 35 from both sides )

5x = 40 ( divide both sides by 5 )

x = 8

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what is the equation of a line, in point-slope form, that passes through (5, -3) and has a slope of 2/3? please help me
Brums [2.3K]

y + 3 = \frac{2}{3} (x - 5)

the equation of a line in point- slope form is

y - b = m ( x - a )

where m is the slope and (a, b) a point on the line

here m =\frac{2}{3} and (a,b) = (5 , - 3 )

y + 3 = \frac{2}{3} (x - 5 ) ← in point-slope form


3 0
3 years ago
_______ is the tendency to solve new problems using procedures that worked before on similar problems.
GrogVix [38]

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Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
If f(x) = 16x – 30 and g(x) = 14x – 6, for which value of x does (f – g)(x) = 0?
Kay [80]

(f – g)(x) = 0

16x-30 -(14x-6) =0

distribute

16x-30 -14x+6 = 0

combine like terms

2x-24=0

add 24 to each side

2x=24

divide by 2

x=12

Answer: x=12


6 0
2 years ago
Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to two decimal places
Montano1993 [528]

The solution of the given equation is :

cosθ = 1/2 when θ = π/3 + 2kπ or 5π/3 + 2kπ

cosθ = -1 when θ = π + 2kπ

Since cos2θ + sin2θ = 1, sin2θ = 1 - cos2θ

So, the given equation is equivalent to 2(1 - cos2θ) - cosθ = 1

-2cos2θ - cosθ + 1 = 0

2cos2θ + cosθ - 1 = 0 (multiplying the entire equation by -1)

(2cosθ - 1)(cosθ + 1) = 0 (taking common)

cosθ = 1/2 or cosθ = -1 (on equating it to zero)

cosθ = 1/2 when θ = π/3 + 2kπ or 5π/3 + 2kπ

cosθ = -1 when θ = π + 2kπ

For more information about trigonometric ratios, visit

brainly.com/question/24496175

3 0
1 year ago
Find the numbers b such that the average value of f(x) = 7 + 10x − 9x2 on the interval [0, b] is equal to 8.
barxatty [35]

Answer:

The numbers b such that the average value of f(x) = 7 +10\cdot x - 9\cdot x^{2} on the interval [0, b] is equal to 8 are b_{1} \approx 1.434 and b_{2} \approx 0.232.

Step-by-step explanation:

The mean value of function within a given interval is given by the following integral:

\bar f = \frac{1}{b-a}\cdot \int\limits^b_a {f(x)} \, dx

If f(x) = 7 +10\cdot x - 9\cdot x^{2}, a = 0, b = b and \bar f = 8, then:

\frac{1}{b}\cdot \int\limits^b_0 {7+10\cdot x -9\cdot x^{2}} \, dx = 8

\frac{7}{b}\int\limits^b_0 \, dx  + \frac{10}{b}  \int\limits^b_0 {x}\, dx - \frac{9}{b}  \int\limits^b_0 {x^{2}}\, dx = 8

\left(\frac{7}{b} \right)\cdot b + \left(\frac{10}{b} \right)\cdot \left(\frac{b^{2}}{2} \right)-\left(\frac{9}{b} \right)\cdot \left(\frac{b^{3}}{3} \right) = 8

7 + 5\cdot b - 3\cdot b^{2} = 8

3\cdot b^{2}-5\cdot b +1 = 0

The roots of this polynomial are determined by the Quadratic Formula:

b_{1} \approx 1.434 and b_{2} \approx 0.232.

The numbers b such that the average value of f(x) = 7 +10\cdot x - 9\cdot x^{2} on the interval [0, b] is equal to 8 are b_{1} \approx 1.434 and b_{2} \approx 0.232.

7 0
3 years ago
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