Answer:
Explanation:
a ) The volume of blood flowing per second throughout the vessel is constant .
a₁ v₁ = a₂ v₂
a₁ and a₂ are cross sectional area at two places of vessel and v₁ and v₂ are velocity of blood at these places .
2A x v₁ = A x .40
v₁ = .20 m /s
b )
Let normal pressure be P₁ when cross sectional area is 2A and at cross sectional area A , pressure is P₂
Applying Bernoulli's theorem
P₁ + 1/2 ρv₁² = P₂ + 1/2 ρv₂²
P₁ - P₂ = 1/2 ρ(v₂² - v₁² )
= .5 x 1060 ( .4² - .2² )
= 63.6 Pa .
Explanation:
PE = KE
mgh = ½ mv²
v = √(2gh)
v = √(2 × 9.8 m/s² × 0.75 m)
v = 3.83 m/s
Answer:
The answer to your question is:
Explanation:
Data
Duane Albert
d = 5 m ; v = 3 m/s v = 4.2 m/s
a) b)
Duane's Albert's
d = 5 + (3)t d = 4.2t
d = 5 + 3t
c) 5 + 3t = 4.2t
4.2t - 3t = 5
1.2t = 5
t = 4.17 s
d)
Duane's
d= 5 + 3(4.17)
d = 17.51 m
Alberts
d = 4.2(4.17)
d = 17.51 m
<span>A photon is characterized by either a wavelength, denoted by λ or equivalently an energy, denoted by E. There is an inverse relationship between the energy of a photon (E) and the wavelength of the light (λ) given by the equation:
E=hc/λ
E=hc/λ
where h is Planck's constant and c is the speed of light. The value of these and other commonly used constants is given in the constants page.
h = 6.626 × 10 -34 joule·s
c = 2.998 Ă— 108 m/s
By multiplying to get a single expression, hc = 1.99 Ă— 10-25 joules-m
E=hc/λ
(6.626*10^-34 J*s) x (2.998Ă—10^8m/s)/ 1.5*10^-8 m
= 1.32*10^-17 J</span>
Yea if you want it to be filled up but if not then no
