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pickupchik [31]
4 years ago
8

A population _____ follows a period of

Physics
2 answers:
Nostrana [21]4 years ago
8 0
A population decline follows a period of overshooting.
tiny-mole [99]4 years ago
8 0

Answer:

a population increase

Explanation:

During the 20th century, the world population increased from 1.65 billion to 6 billion. In 1970, the world's population was half that of today. In less than 15 years, 47% of the population will live in areas already under heavy water stress. In Africa, between 75 and 250 million people will face growing shortages in 2020 due to climate change. The scarcity of some arid and semi-arid regions will have a decisive impact on migration.

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You swing your golf club such that it hits a ball with a force of 15 newtons. It makes contact with the ball for a distance of 0
Viefleur [7K]

Answer:

W = 0.15 J

Explanation:

Given that,

The force acting on the ball, F = 15 N

It makes contact with the ball for a distance of 0.01 m

We need to find the work done on the ball. The work done can be calculated as :

W = Fd

So,

W = (15 × 0.01) J

W = 0.15 J

So, the work done is 0.15 J.

3 0
3 years ago
The coefficient of linear expansion of steel is 12 × 10-6 K-1 . What is the change in length of a 25-m steel bridge span when it
Westkost [7]

Answer:

0.012-m

Explanation:

∆L = α × Lo × (T-To)

α is the coefficient of linear expansion = 12 × 10-6 K-1

Lo = Initial length = 25-m

∆L = Change in length

(T-To) = 40 K

∆L = 12 × 10-6 × 25 × 40

∆L = 0.012-m

4 0
4 years ago
How does newtons law of the universal gravitation help scientist describe the universe
Afina-wow [57]
You need to know everything is made of atoms they are always colliding and they are never still because you'd think that every thing in space is still all the time even if it's not making visibly
5 0
3 years ago
Read 2 more answers
Consider a copper wire with a diameter of 0.450 mm. If you want to cut a piece of the wire so it has a resistance of 3.25 Ω, how
Arisa [49]

Answer:

30.7m

Explanation:

You can use the following equation:

ρ = R * \frac{S}{l}

Where ρ is the resistivity, R is the resistance, S is the Cross-sectional Area and l is the length of the wire.

We issolate l in the equation and solve with the data we have:

l = R * \frac{S}{p} = 3.25 Ω * \frac{0.25 *\pi * ((0.45/1000)^2}{1.68*10^-8}

l =  30.7m

5 0
3 years ago
A parallel-plate capacitor in air has circular plates of radius 2.8 cm separated by 1.1 mm. Charge is flowing onto the upper pla
Hatshy [7]

Answer:

The time rate of change of the electric field between the plates is  \frac{E }{t} =  2.29 *10^{14} \   N \cdot C  \cdot  s^{-1}  

Explanation:

From the question we are told that

    The  radius is  r =  2.8 \ cm  =  0.028 \ m

     The distance of separation is  d =  1.1  \ mm  =  0.0011 \ m

      The  current is  I  =  5 \ A

Generally the electric field generated is mathematically represented as

         E = \frac{q }{ \pi  *  r^2  \epsilon_o  }

Where \epsilon_o is the permitivity of free space with a value

          \epsilon_o  =  8.85*10^{-12 }\   m^{-3} \cdot kg^{-1}\cdot  s^4 \cdot A^2

So the time rate of change of the electric field between the plates is mathematically represented as

        \frac{E }{t} =   \frac{q}{t} *   \frac{1 }{ \pi  *  r^2  \epsilon_o  }

But \frac{q}{t }  =  I

So  

       \frac{E }{t} =   *   \frac{I }{ \pi  *  r^2  \epsilon_o  }

substituting values  

        \frac{E }{t} =   *   \frac{5 }{3.142  *  (0.028)^2 *   8.85 *10^{-12}  }

        \frac{E }{t} =  2.29 *10^{14} \   N \cdot C  \cdot  s^{-1}

5 0
4 years ago
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