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As per the question, the point charge is given as [q] = 6.8 C
The velocity of the charged particle [v] =
The magnetic field [B] = 1.4 T
The angle made between magnetic field and velocity = 15 degree.
We are asked to calculate the magnetic force experienced by the charged particle.
The magnetic force experienced by the charged particle is calculated as -
Magnetic force
i.e F =
Hence, the force experienced by the charged particle is C i.e
Answer:
W = (F1 - mg sin θ) L, W = -μ mg cos θ L
Explanation:
Let's use Newton's second law to find the friction force. In these problems the x axis is taken parallel to the plane and the y axis perpendicular to the plane
Y Axis
N - =
N = W_{y}
X axis
F1 - fr - Wₓ = 0
fr = F1 - Wₓ
Let's use trigonometry to find the components of the weight
sin θ = Wₓ / W
cos θ = W_{y} / W
Wₓ = W sin θ
W_{y} = W cos θ
We substitute
fr = F1 - W sin θ
Work is defined by
W = F .dx
W = F dx cos θ
The friction force is parallel to the plane in the negative direction and the displacement is positive along the plane, so the Angle is 180º and the cos θ= -1
W = -fr x
W = (F1 - mg sin θ) L
Another way to calculate is
fr = μ N
fr = μ W cos θ
the work is
W = -μ mg cos θ L