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Alja [10]
3 years ago
5

MATH HELP please i will mark BRAINLIEST

Mathematics
1 answer:
frutty [35]3 years ago
3 0
I hope this helps! Just follow the instructions.

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Mark's computer weighs 35.769 pounds.
lawyer [7]

Answer:

you have to round up so it would round up to 35.800

Step-by-step explanation:

6 0
2 years ago
Find the area of the shaded segment of the circle
hoa [83]

Answer:

  15.35 m²

Step-by-step explanation:

For a central angle of θ in radians, the area of a segment is ...

   A = (1/2)r²(θ -sin(θ))

The central angle subtending the segment is 120°, or 2π/3 radians. Thus the segment area is ...

  A = (1/2)(5 m)²(2π/3 -sin(2π/3)) = (25 m²)(π/3 -(√3)/4)

  A ≈ 15.35 m² . . . . area of shaded segment

6 0
3 years ago
MATH
Cerrena [4.2K]

Answer:

1. x = 86

2. x = 31

3. x = 64

4. x = 29

Step-by-step explanation:

1. 2x + 8 = 180

-8 -8

2x = 180 (divide both sides by 2 to get x by itself)

2. 3x - 3 = 90

+ 3 +3

3x = 93 (divide both sides by 3 to get x by itself. you divide because 3x is multiplying and you have to do the reverse operation)

3. 2x -5 + x - 7 = 180 (you combine like-terms)

3x -12 = 180

+12 +12

3x = 192 (you divide by 3 on both sides)

4. x + 1 + x + 4 + x - 2 = 90 (combine like-terms)

3x + 3 = 90

-3 -3

3x = 87 (divide both sides by 3)

4 0
2 years ago
Please somebody help me with this math problem. I am terrible at math!
Mekhanik [1.2K]

Answer:

1,-1

Step-by-step explanation:

This is because the numbers are increasing.

M = Gradient M = 1/1 = 1

6 0
3 years ago
Read 2 more answers
Can anyone help me solve this?​
Alecsey [184]

Answer:

Step-by-step explanation:

(\sqrt{z} +\sqrt{22})(\sqrt{z} -\sqrt{22})=35

Subtract both sides from 35

(\sqrt{z}+\sqrt{22} (\sqrt{z} -\sqrt{22})-35=35-35

Simplify:

(\sqrt{z})^{2} -57=0

Factor (\sqrt{z})^{2}  -57: (\sqrt{z}+\sqrt{57}) (\sqrt{z}-\sqrt{57})=0

\sqrt{z} +\sqrt{57}=0    or    \sqrt{z}  -\sqrt{57}=0

\sqrt{z} +\sqrt{57} =0: No Solution for Z

\sqrt{z} -\sqrt{57} =0: z=57

Your answer will be z=57

and No solution

8 0
2 years ago
Read 2 more answers
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