<span>Important information to solve the exercise :
Substance ΔHf (kJ/mol):
HCl(g)= −92.0 </span><span>kJ/mol
Al(OH)3(s)= −1277.0 </span><span><span>kJ/mol
</span> H2O(l)= −285.8 </span><span>kJ/mol
AlCl3(s) =−705.6 </span><span>kJ/mol
</span><span>Al(OH)3(s)+3HCl(g)→AlCl3(s)+3H2O(l)
reactants products
products- reactants:</span><span>
(−705.6) + (3 x −285.8) - ( −1277.0 ) - (3 x −92.0 ) = - 10.0 </span>kJ per mole at 25°C
<span>
</span>
The radii of most atoms fall within range of 5 × 10⁻¹¹ m to 2 × 10⁻¹⁰ m
Answer:
no
Explanation:
you would need an electron microscope to see atoms.
The answer is (3). The number of Sr is the same so if the compound has the smallest gram formula mass, it has the highest percent composition by mass of strontium. So the answer is (3).
Answer:
D. 0.60 L.
Explanation:
- For the acid-base neutralization, we have the role:
The no. of millimoles of acid is equal to that of the base at the neutralization.
<em>∴ (XMV) NaOH = (XMV) H₂SO₄.</em>
X is the no. of reproducible H⁺ (for acid) or OH⁻ (for base),
M is the molarity.
V is the volume.
X = 1, M = 4.0 M, V = ??? L.
X = 2, M = 4.0 M, V = 0.3 L.
∴ V of NaOH = (XMV) H₂SO₄/(XM) NaOH = (2)(4.0 M)(0.3 L)/(1)(4.0 M) = 0.6 L.
<em>So, the right choice is: D. 0.60 L.</em>
<em></em>