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Basile [38]
3 years ago
8

Determine the density of chlorine gas at 22C and 1.00 atm pressure

Chemistry
1 answer:
polet [3.4K]3 years ago
3 0
 <span>T = 22.0 + 273.15 =295.15 K 
Molar mass Cl2 = 70.906 g/mol 
d = molar mass x p / RT = 70.906 x 1.00 / 0.0821 x 295.15 = 2.93 g/L
Hope this isn't to much? If it doesn't help you know where to find me :)</span>
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Find the value of 6 +<br>6 +<br>6 + 16 + vo​
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6

Explanation:

the value is 6 because its an even number

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The amplitude of a wave tells you how fast the wave is moving. True False
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What volume would a sample of gas occupy in LITERS at 0.985 atmospheres and a volume of 3.65 liters if the pressure were raised
musickatia [10]

Answer:

3.18 L

Explanation:

Step 1: Given data

  • Initial pressure (P₁): 0.985 atm
  • Initial volume (V₁): 3.65 L
  • Final pressure (P₂): 861.0 mmHg
  • Final volume (V₂): ?

Step 2: Convert P₁ to mmHg

We will use the conversion factor 1 atm = 760 mmHg.

0.985 atm × 760 mmHg/1 atm = 749 mmHg

Step 3: Calculate the final volume of the gas

Assuming ideal behavior and constant temperature, we can calculate the final volume using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁/P₂

V₂ = 749 mmHg × 3.65 L/861.0 mmHg = 3.18 L

7 0
3 years ago
3.0 cm x 4.0 cm x 1.0 cm<br><br>[?]cm^3​
CaHeK987 [17]

Explanation:

<em>Hi</em><em> </em><em>there</em><em>!</em><em>!</em>

<em>you</em><em> </em><em>asked</em><em> </em><em>to</em><em> </em><em>multiply</em><em> </em><em>these</em><em> </em><em>all</em><em> </em><em>right</em><em>,</em>

<em>you</em><em> </em><em>can</em><em> </em><em>simply</em><em> </em><em>multiply</em><em> </em><em>it</em><em> </em><em>,</em>

<em>=</em><em>3</em><em>cm</em><em> </em><em>×</em><em> </em><em>4</em><em> </em><em>cm</em><em> </em><em>×</em><em> </em><em>1</em><em>cm</em>

<em>=</em><em> </em><em>1</em><em>2</em><em>cm</em><em>^</em><em>2</em><em>×</em><em>1</em><em>cm</em><em> </em><em> </em><em> </em><em> </em><em>(</em><em>4</em><em>×</em><em>3</em><em>=</em><em>1</em><em>2</em><em>)</em>

<em>=</em><em> </em><em>1</em><em>2</em><em>cm</em><em>^</em><em>3</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>(</em><em>1</em><em>2</em><em>×</em><em>1</em><em>=</em><em>1</em><em>2</em><em>)</em>

<em>Therefore</em><em>, </em><em> </em><em>the</em><em>answer is</em><em> </em><em>1</em><em>2</em><em> </em><em>cm</em><em>^</em><em>3</em><em>.</em>

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em>

4 0
3 years ago
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