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Leya [2.2K]
3 years ago
14

What is the general form for the simplest type of acid-base reaction?

Chemistry
1 answer:
omeli [17]3 years ago
5 0
HA +BOH→BA+H2O neutralisation reaction for monobasic acid monoacidic base
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In an electron dot diagram of propane (C3H8), how many double bonds are present?
NeX [460]

Answer:- none

Explanations:- For naming hydrocarbons we use the suffix -ane, -ene and -yne.

-ane is used when we have only single bonds between all carbons. -ene is used if there is any double bond between two carbons and the -yne is used if there is any triple bond between two carbons.

The given name of the compound is propane. It ends at -ane and so it's an alkane and must have single bonds between all the carbons it has. So, there are zero double bonds present in C_3H_8 .

This is also clear from the below lewis dot structure of the compound.


4 0
3 years ago
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Recording a person’s fingerprints using ink or digital imaging is called a(n)____.
NNADVOKAT [17]
It is called a dactyloscopy
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2 years ago
When air bags inflate, nitrogen gas is formed from sodium azide, along with solid sodium. what reaction category is this?
adell [148]
The answer is
alkaline silocate
7 0
3 years ago
Help I’m timed!
Anastaziya [24]

Answer: i could be incorrect but im pretty sure the answer is, Gas surface with no rings.

Explanation:

s-s-s-science!

3 0
2 years ago
If 0.0106 g of a gas dissolves in 0.792 L of water at 0.321 atm, what quantity of this gas (in grams) will dissolve at 5.73 atm?
Alex73 [517]

Answer:

0.189 g.

Explanation:

  • This problem is an application on <em>Henry's law.</em>
  • Henry's law states that the solubility of a gas in a liquid is directly proportional to its partial pressure of the gas above the liquid.
  • Solubility of the gas ∝ partial pressure
  • If we have different solubility at different pressures, we can express Henry's law as:

<em>S₁/P₁ = S₂/P₂,</em>

S₁ = 0.0106/0.792 = 0.0134 g/L and P₁ = 0.321 atm

S₂ = ??? g/L and P₂ = 5.73 atm

  • So, The solubility of the gas at 5.73 atm (S₂) = S₁.P₂/P₁ = (0.0134 g/L x 5.73 atm) / (0.321 atm) = 0.239 g/L.

<em>The quantity in (g) = S₂ x V = (0.239 g/L)(0.792 L) = 0.189 g.</em>

<em></em>

8 0
3 years ago
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