The kinetic energy of gas particles depends on temperature. Greater the temperature higher will be the average kinetic energy
Kinetic energy is related to the temperature as:
KE = 3/2 kT
where k = Boltzmann constant
T = temperature
In the given example, since the temperature of O2 gas is maintained at room temperature, the average KE will also remain constant.
The fifth postulate of the kinetic molecular theory which states that the temperature of the gas depends on the average KE of the particles of the gas explains the above observation.
Sorry I don’t know the answer I am just Thea answer is whatever the person you answer Rushdie you answer the answer negative and I am trying something I am so sorry
Answer:
B. CH3COOH pH > 4.7 (4.8)
Explanation:
- CH3COOH + NaOH ↔ CH3COONa + H2O
- CH3COONa + NaOH ↔ CH3COONa
∴ mol NaOH = (5 E-3 L)*(0.10 mol/L) = 5 E-4 mol
⇒ mol CH3COOH = (0.05 L)*(0.20 mol/L) = 0.01 mol
⇒ <em>C</em> CH3COOH = (0.01 mol - 5 E-4 mol) / (0.105 L)
⇒ <em>C</em> CH3COOH = 0.0905 M
∴ mol CH3COONa = (0.05 L )*(0.20 mol/L) = 0.01 mol
⇒ <em>C</em> CH3COONa = (0.01 mol + 5 E-4 mol) / (0.105 L )
⇒ <em>C</em> CH3COONa = 0.1 M
∴ Ka = ([H3O+]*(0.1 + [H3O+])) / (0.0905 - [H3O+]) = 1.75 E-5
⇒ 0.1[H3O+] + [H3O+]² = (1.75 E-5)*(0.0905 - [H3O+])
⇒ [H3O+]² 0.1[H3O+] = 1.584 E-6 - 1.75 E-5[H3O+]
⇒ [H3O+]² + 0.1000175[H3O+] - 1.584 E-6 = 0
⇒ [H3O+] = 1.5835 E-5 M
∴ pH = - Log [H3O+]
⇒ pH = - Log (1.5835 E-5)
⇒ pH = 4.8004 > 4.7
Answer:
done this before in my science class
Explanation:
the hole by the cap will have slightly more coming out at first due to all the toothpaste pushing forward, but over time, the middle will get more do to all the front end of the toothpaste being pushed out first
(sorry if that sounded confusing im tired, heres a cat)
