If there are 4 grams of product produced by the chemical reaction, how many grams of reactant were consumed?
2 answers:
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S₂O₈²⁻
(aq) + 2I⁻
(aq) → I₂(aq) + 2SO₄
²⁻(aq)
2S₂O₃²⁻
(aq) + I₂(aq) → S₄O₆²⁻
(aq) + 2I⁻
(aq)
<u>Explanation:</u>
S₂O₈²⁻
(aq) + 2I⁻
(aq) → I₂(aq) + 2SO₄
²⁻(aq)
To measure the rate of this reaction we must measure the rate of concentration change of one of the reactants or products. To do this, we will include (to the reacting S₂O₈
²⁻ and I⁻
i) a small amount of sodium thiosulfate, Na₂S₂O₃,
ii) some starch indicator.
The added Na₂S₂O₃ does not interfere with the rate of above reaction, but it does consume the I₂ as soon as it is formed.
2S₂O₃²⁻
(aq) + I₂(aq) → S₄O₆²⁻
(aq) + 2I⁻
(aq)
This reaction is much faster than the previous, so the conversion of I2 back to I⁻ is essentially instantaneous.
Answer : The pH of the solution is, 5.24
Explanation :
First we have to calculate the volume of
Formula used :
where,
are the initial molarity and volume of
.
are the final molarity and volume of
.
We are given:
Putting values in above equation, we get:
Now we have to calculate the total volume of solution.
Total volume of solution = Volume of + Volume of
Total volume of solution = 160.0 mL + 1086.79 mL
Total volume of solution = 1246.79 mL
Now we have to calculate the Concentration of salt.
Now we have to calculate the pH of the solution.
At equivalence point,
Thus, the pH of the solution is, 5.24