Answer: a) . Ammonia is the limiting reagent
b. Oxygen is left over and 0.1375 g of oxygen is left over.
c. The theoretical yield of  is 35.29 g.
 is 35.29 g.
d. The theoretical yield of  is 31.74 g.
 is 31.74 g.
Explanation: 
To calculate the number of moles, we use the equation:
 
   
For  
Given mass of ammonia = 20.0 g
Molar mass of ammonia = 17.031 g/mol
Putting values in equation 1, we get:
 
For 
Given mass of oxygen gas = 50.0 g
Molar mass of oxygen gas = 32 g/mol
Putting values in equation 1, we get:
 
The chemical equation for the reaction is
 
By Stoichiometry of the reaction:
4 moles of ammonia reacts with = 5 moles of oxygen
So 1.17 moles of ammonia will react with =  of oxygen
 of oxygen
As, given amount of oxygen is more than the required amount. So, it is considered as an excess reagent and (1.6-1.4625)= 0.1375 g of oxygen is left unreacted.
Thus ammonia is considered as a limiting reagent because it limits the formation of product.
1. By Stoichiometry of the reaction:
4 moles of ammonia produces = 4 moles of 
1.17 moles of ammonia will produce =  of
 of 
Mass of  
Thus Theoretical yield of  is 35.29 grams.
 is 35.29 grams.
2. By Stoichiometry of the reaction:
4 moles of ammonia produces = 6 moles of 
1.2 moles of ammonia will produce =  of
 of 
Mass of  
  
Thus Theoretical yield of  is 31.74 grams.
 is 31.74 grams.