Answer:
half life = 25 days
Explanation:
Given data:
Total amount of sample = 40 mg
Sample left after 50 days = 10 mg
Half life of P³³ = ?
Solution:
<em>1st step:</em>
when time is zero = 40 mg
1 half life = 40/2 = 20 mg
2 half life = 20/ 2= 10 mg
<em>2nd step:</em>
<em>Elapsed time/ half life = HL</em>
half life = 50 days/ 2
half life = 25 days
Answer:
C₂H₄O₂
Explanation:
Step 1: Divide each percentage by the atomic mass of the element
C: 40.00/12.01 = 3.331
H: 6.67/1.01 = 6.60
O: 53.33/16.00 = 3.333
Step 2: Divide all the numbers by the smallest one
C: 3.331/3.331 = 1
H: 6.60/3.331 ≈ 2
O: 3.333/3.331 ≈ 1
The empirical formula is CH₂O, with a molecular weight of 12 g/mol + 2 × 1 g/mol + 16 g/mol = 30 g/mol. The molecular weight of the compound must be a product of 30, such as 60 (between 55 and 62 g/mol). Since we have to multiply by 2 (30 to 60) to get to the molecular weight of the compound, we also have to multiply the empirical formula by 2 to get the chemical formula of the compound.
CH₂O × 2 = C₂H₄O₂
I’m assuming this is a true and false question. The answer is true. Phosphorus has a larger atomic mass. Phosphorus is number 15 on the periodic table. Phosphorus is a non-metal.
<span>CO2 (carbon) is the main product that results from burning paper. The paper is the reactant
When paper burns in a fire, the reactants are mostly carbon (the main substance in the paper) and oxygen (from the air).Co2
If paper is loaded with CaCO3 such as cigarette paper, CaCO3 decompose in to CaO and CO2</span>
