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EleoNora [17]
3 years ago
5

Suppose that 26.89 ml of vinegar solution requires 33.23 ml of the 0.09892 m sodium hydroxide solution to reach the endpoint. ca

lculate the molar concentration of the vinegar solution.
Chemistry
1 answer:
nata0808 [166]3 years ago
5 0
Number of millimoles of NaOH consumed in present titration =<span>33.23 X 0.09892
                                                                                                 = 3.287

Thus, number of millimoles of vinegar present in sample = 3.287

Now, Molarity of vinegar solution = </span>\frac{\text{number of millimoles of vinegar}}{\text{volume of solution (ml)}}
<span>                                                     = </span>\frac{3.287}{26.89}
<span>                                                     = 0.1222 mol/dm3

Molar concentration of vinegar present in sample solution is 0.1222 M </span>
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A mixture of0.161 moles of C is reacted with 0.117 moles of O2 in a sealed, 10.0 L-vessel at 500.0 K, producing a mixture of CO
labwork [276]

Answer:

number of moles of CO2 is 0.054

number of moles of CO is 0.107

number of moles of O2 remaining is 0.01 mole

mole fraction of CO is 0.63

Explanation:

Firstly, we write the equation of reaction;

3C(s) +2O2(g) → CO2(g) +2CO(g)

Now, we proceed.

From the written equation, we can deduce that

3 mol C = 2 mol O2 = 1 mol CO2 = 2 mol CO

No of mol of C reacted = 0.161 mol

limiting reactant according to the question is Carbon

a. no of mol of CO2 formed = 0.161*1/3 = 0.054 moles ( no of moles of CO2 formed is one-third of no of moles of carbon reacted. This is obtainable from their mole ratio 1:3)

b. no of mol of CO formed = 0.161*2/3 = 0.107 mol

c. no of mol of O2 remaining = 0.117 - (0.151*2/3) = 0.117-0.107 = 0.01 mole

d. mole fraction of CO = no of mol of CO/Total number of moles

= 0.107/(0.107+0.054+0.01)

= 0.625730994152 which is approximately 0.63

5 0
3 years ago
A dosage is prescribed as 4.00 mg of medicine per kg of body weight.What dose should be given to a 112 pound person
vodka [1.7K]

Answer:

203.64 mg

Explanation:

112/2.2= 50.91

50.91x4.00= 203.64

4 0
3 years ago
How many grams of sodium bicarbonate are needed to completely react with a 0.892 m phosphoric acid solution that contains to 45.
SVETLANKA909090 [29]

Answer:

umm idk if I was right or not

7 0
3 years ago
Can compound take part in chemical reaction?
Fittoniya [83]

Answer:

YES!

Explanation:

3 0
3 years ago
It takes 839./kJmol to break a carbon-carbon triple bond. Calculate the maximum wavelength of light for which a carbon-carbon tr
tresset_1 [31]

Answer:

The maximum wavelength of light for which a carbon-carbon triple bond could be broken by absorbing a single photon is 143 nm.

Explanation:

It takes 839 kJ/mol to break a carbon-carbon triple bond.

Energy required to break 1 mole of carbon-carbon triple bond = E = 839 kJ

E = 839 kJ/mol = 839,000 J/mol

Energy required to break 1 carbon-carbon triple bond = E'

E'=\frac{ 839,000 J/mol}{N_A}=\frac{839,000 J}{6.022\times 10^{23} mol^{-1}}=1.393\times 10^{-18} J

The energy require to single carbon-carbon triple bond will corresponds to wavelength which is required to break the bond.

E'=\frac{hc}{\lambda } (Using planks equation)

\lambda =\frac{6.626\times 10^{-34} Js\times 3\times 10^8 m/s}{1.393\times 10^{-18} J}

\lambda =1.427\times 10^{-7} m =142.7 nm = 143 nm

(1 m = 10^9 nm)

The maximum wavelength of light for which a carbon-carbon triple bond could be broken by absorbing a single photon is 143 nm.

6 0
3 years ago
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