Question

Aluminum foil is often incorrectly termed tin foil. If the density of tin is 7.28g/cm³,what is the thickness of a piece of tin foil that measures 5.70cm by 4.25cm and has a mass of 0.655g

Answer 1

To answer this question, you should first find the volume:7.28 g/ mL x .655 g / v = 0.08997 mL
volume = L x W x H, but thickness is the width. So rearranging the formula, the formula is v / l x h.
The thickness is found after dividing the volume by its length and width:
.08997 / (5.70) (4.25) = .004 cm is the thickness.

Answer 2

Answer:

The thickness of the piece of foil is $3.71*10^{-3}cm$

Explanation:

Please see the figure below that represents the aluminum foil. The volume of the tin foil will be:

V = length * width * thickness

Now, the density of tin is given by the expression:

ρ = $\frac{m}{V}$

where m is the mass of the tin and V is the volume of it.

From the expression for the density we have:

V = m/ρ

And replacing the expression for the Volume of the tin, we have:

length*width*thickness = m/ρ

so

thickness = m/(ρ*length*width)

And replacing the given values we have:

$thickness=\frac{0.655g}{7.28\frac{g}{cm^{3}}*5.70cm*4.25cm}$

$thickness=\frac{0.655g}{176,358\frac{g}{cm}}$

$thickness=3.71*10^{-3}cm$