According to Arrhenius, an acid is a substance that dissociates to give protons, whereas a base dissociates to give hydroxide ions in an aqueous solution.

Therefore, a chemical reaction in which an Arrhenius acid reacts with an Arrhenius base to give salt and water, is known as a Neutralization reaction.

For example: Neutralization reaction of hydrochloric acid (HCl) and sodium hydroxide (NaOH)

A strong acid, hydrochloric acid (HCl) reacts with a strong base, sodium hydroxide (NaOH) to give salt, sodium chloride (NaCl) and water (H₂O).

The chemical equation for this Neutralization reaction:

HCl (acid) + NaOH (Base) → NaCl (Salt) + H₂O (Water)

Therefore, sodium chloride (NaCl) is the salt formed during the chemical reaction of hydrochloric acid (HCl) and sodium hydroxide (NaOH).

3 0

3 years ago

Find the empirical formula of the following compound: 0.77 mol of iron atoms combined with 1.0 mol of oxygen atoms.

eimsori [14]

The empirical formula is Fe₃O₄.

The empirical formula is the simplest whole-number ratio of atoms in a compound.

The ratio of atoms is the same as the ratio of moles, so our job is to calculate the molar ratio of Fe to O.

I like to summarize the calculations in a table.

Element Moles Ratio¹ ×3² Integers³

Fe 0.77 1 3 3

O 1.0 1.3 3.9 4

¹ To get the molar ratio, you divide each number of moles by the smallest number (0.77).

² If the ratio is not close to an integer, multiply by a number (in this case, 3) to get numbers that are close to integers.

³ Round off these numbers to integers (3 and 4).

The empirical formula is Fe₃O₄.

7 0

3 years ago

A 100 kg tree gets struck by lightning and is burned completely to ash. A scientist gathers up all the ash and weighs it to find

Oksi-84 [34.3K]

Answer:

Evaporated via combustion.

Explanation:

The loss on ignition (LOI) and Ash content are inorganic analytical techniques used to determine the percentage by mass of hydrocarbon in compounds. This process allows volatile matter and possibly impurities found in a material to evaporate, leaving behind the true chemical constituents of the material.

The 10kg lost could be moisture content of the tree, or other volatile matter which has escaped on combustion of the tree.

6 0

3 years ago

Determine the specific heat of a 70 g sample of material that absorbed 96 J as it was heated from 293 K to 313 K

Damm [24]

This problem is providing us with the mass (70 g), absorbed heat (96 J) and initial and final temperatures (293 K and 313 K, respectively) so the specific heat of the material is required and found to be 0.0686 J/(g*K) as shown below:

<h3>Calorimetry:</h3>

In chemistry, we can go over calorimetry by writing the following relationship among heat, mass, specific heat and temperature change:

$Q=mC(T_f-T_i)$

Thus, one can get the specific heat by solving for C in the previous equation:

$C=\frac{Q}{m(T_f-T_i)}$

Hence, we can plug in the given data to obtain:

$C=\frac{96J}{70g(313K-293K)}\\ \\C=0.0686\frac{J}{g*K}$

Learn more about calorimetry: brainly.com/question/1407669

5 0

2 years ago