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CaHeK987 [17]
4 years ago
5

A student uses 0.10 M HCl to simulate the acid concentration in the stomach. What volume( in ml) of “stomach acid” reacts with a

tablet that contains 0.10 g of magnesium hydroxide?
Chemistry
1 answer:
Tpy6a [65]4 years ago
3 0

Given, concentration of HCl = 0.10 M

Mass of Mg(OH)₂ = 0.10 g

Molar mass of Mg(OH)₂ = 58.3197 g/mol

Moles  = mass /molar mass

Mole of Mg(OH)₂ = 0.10 g/ 58.3197 g/mol

Mole of Mg(OH)₂ = 1.71

Mg(OH)₂(s) + 2HCl(aq) → MgCl₂(aq) + 2H₂O(l)

According to the balanced equation 1 moles of Mg(OH)₂ reacts with 2 moles of HCl.

Therefore, 1.71  moles of Mg(OH)₂ reacts with (2 x 1.71) or 3.42 moles of HCl

Molarity = moles / volume in L

Volume of HCl = 3.42 moles of HCl / 0.10 M HCl

Volume of HCl = 34.2 L or 34200 ml

34200 ml of “stomach acid” reacts with a tablet that contains 0.10 g of magnesium hydroxide.

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Answer:

The solution is not ideal.

The relative strengths of the solute-solvent interactions are greater  compared to the solute-solute and solvent-solvent interactions

Explanation:

The total vapor pressure is the sum of the partial pressures of  water and methanol, and they are calculated by the Raoult´s law equation:

Pₐ = Xₐ Pºₐ, where  Pₐ is the partial pressure of component A

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Ptotal = PH2O  + PCH3OH  = 17.3 torr + 176.1 torr = 193.4 torr

This pressure is less than the experimental value of 211 torr. So the solution is not ideal. The relative strength of the solute-solvent interactions are greater than the solute-solute and solvent-solvent interactions.

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