1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sammy [17]
3 years ago
11

What is the typical percentage (by mass of elements other than hydrogen and helium in stars that are forming right now in the vi

cinity of the sun?
Chemistry
1 answer:
Ipatiy [6.2K]3 years ago
5 0
Considering mass percentages, stars in the vicinity of the sun contain only 2% other elements by mass. Other than the main components, hydrogen and helium, stars have some heavier elements such as carbon, nitrogen, oxygen and iron. These elements are found near or in the star's core and are ejected into space when the star dies. 
You might be interested in
Question number 10 & 11, answer please and thank you
nika2105 [10]

Answer:

molarity = moles of solution/liters of solution

molarity = 1 mole/2 liters

molarity = 0.5 M

molarity = 50 moles/200 kg

molarity = 0.25 M

Explanation:

3 0
3 years ago
How are scented candles made?
marysya [2.9K]

Answer:

The aroma from a lighted scented candle is released through the evaporation of the fragrance from the hot wax pool and from the solid candle itself. Like unscented candles, properly-formulated scented candles will primarily produce water vapor and carbon dioxide when burned

Explanation:

7 0
3 years ago
Read 2 more answers
Which substance made up minerals
Alenkasestr [34]

Answer

Chemical element

Explanation:

4 0
3 years ago
Read 2 more answers
Why do you think it is important to use the same blanace throughout the entire experiment?
Zepler [3.9K]

It is important to use the same balance throughout the entire experiment since the calibration of each balance is not the same and changing balances could result in a systematic error.

There are three types of errors that could affect the results of the experiment. The effect of random or indeterminate errors is hard to predict, its effect on the results of the experiment could be different every time. The second type of error is the systematic or determinate error, which causes a shift in results in a specific direction. The last type of error in an experiment is human error.

The type of error that could be related to the use of different balances throughout the experiment is the systematic error. Instruments could be a source of error especially if they are poorly calibrated. Also, analytical balances are calibrated differently which may result in inaccuracy in the weighing of chemicals.

To learn more, please refer to brainly.com/question/11541675.

#SPJ4

6 0
2 years ago
For the reaction A +B+ C D E, the initial reaction rate was measured for various initial concentrations of reactants. The follow
lora16 [44]

Answer:

Rate constant of the reaction is 3.3\times 10^{-3} M^{-2} s^{-1}.

Explanation:

A + B + C → D + E

Let the balanced reaction be ;

aA + bB + cC → dD + eE

Expression of rate law of the reaction will be written as:

R=k[A]^a[B]^b[C]^c

Rate(R) of the reaction in trail 1 ,when :

[A]=0.30 M,[B]=0.30 M,[C]=0.30 M

R=9.0\times 10^{-5} M/s

9.0\times 10^{-5} M/s=k[0.30 M]^a[0.30 M]^b[0.30 M]^c...[1]

Rate(R) of the reaction in trail 2 ,when :

[A]=0.30 M,[B]=0.30 M,[C]=0.90 M

R=2.7\times 10^{-4} M/s

2.7\times 10^{-4} M/s=k[0.30 M]^a[0.30 M]^b[0.90 M]^c...[2]

Rate(R) of the reaction in trail 3 ,when :

[A]=0.60 M,[B]=0.30 M,[C]=0.30 M

R=3.6\times 10^{-4} M/s

3.6\times 10^{-4} M/s=k[0.60 M]^a[0.30 M]^b[0.30 M]^c...[3]

Rate(R) of the reaction in trail 4 ,when :

[A]=0.60 M,[B]=0.60 M,[C]=0.30 M

R=3.6\times 10^{-4} M/s

3.6\times 10^{-4} M/s=k[0.60 M]^a[0.60 M]^b[0.30 M]^c...[4]

By [1] ÷ [2], we get value of c ;

c = 1

By [3] ÷ [4], we get value of b ;

b = 0

By [2] ÷ [3], we get value of a ;

a = 2

Rate law of reaction is :

R=k[A]^2[B]^0[C]^1

Rate constant of the reaction = k

9.0\times 10^{-5} M/s=k[0.30 M]^2[0.30 M]^0[0.30 M]^1

k=\frac{9.0\times 10^{-5} M/s}{[0.30 M]^2[0.30 M]^0[0.30 M]^1}

k=3.3\times 10^{-3} M^{-2} s^{-1}

7 0
3 years ago
Other questions:
  • What characteristic must be true of a good hypothesis
    8·1 answer
  • How many atoms are in KCI
    12·1 answer
  • In your own words, describe what is the role or function of the neutron in the atom's nucleus
    15·2 answers
  • Consider the following equilibrium reaction.
    8·2 answers
  • Why do some earthquakes cause more damage than others?
    9·2 answers
  • TRUE OR FALSE<br> “Acids are electrolytes”
    5·2 answers
  • Suppose you want to make an acetic acid/acetate buffer to a pH of 5.00 using 10.0 mL of 1.00 M acetic acid solution. How many mi
    8·1 answer
  • The volume of a gas is decreased from 100 liters at 173.0°C to 50 liters at a constant pressure. After the decrease in volume, w
    10·1 answer
  • QUESTION:
    11·2 answers
  • Carbon tetrafluoride, CF4 contains four identical C-F bonds. Fluorine is more electronegative than carbon. How will this impact
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!