<em> $ 434.40</em>
<em>41 miles ............ 1 gallon</em>
<em>4700 miles .......x gallon</em>
<em>x = 4700×1/41 = 114.63 gallons</em>
<em />
<em>114.63 gallons×$3.79 ≈ $ 434.40</em>
Key concepts
Density
Mass
Volume
Concentration
Buoyancy
Water
Answer:
Explanation:
percentage abundance of third isotope = 100 - ( 78.900 + 10.009)
= 11.091 %
Atomic mass
24.1687 x .789 + 25.4830 x .10009 + 24.305 x .11091
19.069 + 2.5506 + 2.69566
= 24.3153 amu
Answer:
0.252 mol
Explanation:
<em>Given the following reaction: </em>
<em>Cu + 2 AgNO₃ → 2 Ag + Cu(NO₃)₂</em>
<em>How many moles of Ag will be produced from 16.0 g Cu, assuming AgNO3 is available in excess.</em>
First, we write the balanced equation.
Cu + 2 AgNO₃ → 2 Ag + Cu(NO₃)₂
We can establish the following relations.
- The molar mass of Cu is 63.55 g/mol.
- The molar ratio of Cu to Ag is 1:1.
The moles of Ag produced from 16.0 g of Cu are:

The answer is Ice spheres