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enyata [817]
2 years ago
5

Once a slide is prepared and placed onto the microscope, the magnification and focus need to be altered. Describe how to change

the magnification and bring the image into focus using a light microscope like the one in the simulation.
Chemistry
2 answers:
Harlamova29_29 [7]2 years ago
5 0

Answer:

我實際上不知道答案,我只是為了點數而這樣做,哈哈,祝你好運哈哈

Explanation:

我實際上不知道答案,我只是為了點我實際上不知道答案,我只是為了點數而這樣做,哈哈,祝你好運哈哈數而這樣做,哈哈,祝你好運哈哈

Evgen [1.6K]2 years ago
5 0

Answer:

They said: I don’t actually know the answer, I just do it for points, haha, good luck haha

Explanation:

I actually don’t know the answer, I’m just for the point I don’t actually know the answer, I just do it for the point, haha, good luck haha ​​and do this, haha, good luck haha

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7.7. A painter leans his back against a painted wall while looking into a 1m long mirror at the opposite end of a rectangular ro
Karolina [17]

Answer:

Correct answer is b) 2m

Explanation:

8 0
3 years ago
If an area has high air pressure and low humidity, what type of weather will it most likely have?
elixir [45]

Aloha~! My name is Zalgo and I am here to help you out today. Those sort of conditions could be fore-boding/foreshadowing/warning that there will soon be a storm or that it will rain quite a lot. In the case of it being a storm, you should be a small room where there are no windows and nothing that is small that will fly towards you that could kill you.

I hope that this helps! :D

"Stay Brainly and stay proud!" - Zalgo

4 0
3 years ago
Read 2 more answers
(1 pt) You have 250.0 mL of 0.136 M HCl. Using a volumetric pipet, you take 25.00 mL of that solution, place it in a 100.00 ml v
alexdok [17]

Answer:

0.034M HCl is the concentration of the diluted solution

Explanation:

You take, initially, 25.00mL of the 0.136M HCl. Then, you dilute the solution to 100.00mL. The solution is diluted:

100.00mL / 25.00mL = 4. The solution was diluted 4 times.

That means the concentration of the diluted solution is:

0.136M / 4 =

<h3>0.034M HCl is the concentration of the diluted solution</h3>
7 0
3 years ago
Theory that the lithosphere is divided into tectonic plates that slowly move on
vitfil [10]
Pute because I’m smart and I know the right answer
5 0
3 years ago
Name the following ionic compounds, keeping in mind that a transition metal cation must include its charge. ____________________
Lilit [14]

Answer :

(a) The name for TiO_2 is titanium(IV) oxide.

(b) The name for BaCl_2 is barium chloride.

(c) The name for CuCl_3 is copper(III) chloride.

(d) The name for KI is potassium iodide.

(e) The name for SrCl_2 is strontium chloride.

(f) The name for CuBr_2 is copper(II) bromide.

Explanation :

Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.

Ionic compound are usually formed when a metal reacts with a non-metal.

The nomenclature of ionic compounds is given by:

1. Positive ion is written first.

2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.

3. In case of transition metals, the oxidation state are written in roman numerals in bracket in-front of positive ions.

(a) TiO_2

TiO_2 is an ionic compound because titanium element is a metal and oxygen element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on tin is (+4) and the the charge on oxygen is (-2). Thus, the name for TiO_2 is titanium(IV) oxide.

(b) BaCl_2

BaCl_2 is an ionic compound because barium element is a metal and chlorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on barium is (+2) and the the charge on chlorine is (-1). Thus, the name for BaCl_2 is barium chloride.

(c) CuCl_3

CuCl_3 is an ionic compound because copper element is a metal and chlorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on copper is (+3) and the the charge on chlorine is (-1). Thus, the name for CuCl_3 is copper(III) chloride.

(d) KI

KI is an ionic compound because potassium element is a metal and iodine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on potassium is (+1) and the the charge on iodine is (-1). Thus, the name for KI is potassium iodide.

(e) SrCl_2

SrCl_2 is an ionic compound because strontium element is a metal and chlorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on strontium is (+2) and the the charge on chlorine is (-1). Thus, the name for SrCl_2 is strontium chloride.

(f) CuBr_2

CuBr_2 is an ionic compound because copper element is a metal and bromine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on copper is (+2) and the the charge on bromine is (-1). Thus, the name for CuBr_2 is copper(II) bromide.

3 0
3 years ago
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