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Anna11 [10]
4 years ago
9

A chemist measures the amount of iodine solid produced during an experiment. she finds that 1.6 g of iodine solid is produced. c

alculate the number of moles of iodine solid produced.
Chemistry
1 answer:
Yakvenalex [24]4 years ago
3 0

Mass of iodine solid produced = 1.6 g

Iodine solid has a molecular formula : I2

Atomic mass of iodine = 126.904 g/mol

Therefore, molar mass of I2 solid = 2* 126.904 = 253.808 g/mol

Number of moles of a given substance is the ratio of its mass to the molar mass

# moles of I2 solid = mass of I2 solid/molar mass = 1.6 g/253.808 = 0.00630 moles

Hence, the # moles of iodine solid produced is 0.00630 moles

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Answer : The reaction rate at 3^oC,24^oC,40^oC\text{ and }65^oC are 36mg/L/sec,142mg/L/sec,190mg/L/sec\text{ and }352mg/L/sec

Solution : Given,

Mass of tablet = 1000 mg

Volume of water = 0.200 L

Formula used :

\text{Reaction rate}=\frac{\text{Mass of tablet}/\text{Volume of water}}{\text{Reaction time}}

Now we have to calculate the reaction rate at different temperatures and reaction time.

\text{Reaction rate at }3^oC=\frac{1000mg/0.200L}{138.5sec}=\frac{5000mg/L}{138.5sec}=36mg/L/sec

\text{Reaction rate at }24^oC=\frac{1000mg/0.200L}{34.2sec}=\frac{5000mg/L}{34.2sec}=142mg/L/sec

\text{Reaction rate at }40^oC=\frac{1000mg/0.200L}{26.3sec}=\frac{5000mg/L}{26.3sec}=190mg/L/sec

\text{Reaction rate at }65^oC=\frac{1000mg/0.200L}{14.2sec}=\frac{5000mg/L}{14.2sec}=352mg/L/sec

Therefore, the reaction rate at 3^oC,24^oC,40^oC\text{ and }65^oC are 36mg/L/sec,142mg/L/sec,190mg/L/sec\text{ and }352mg/L/sec

5 0
4 years ago
Read 2 more answers
A chemist needs to create a series of standard Cu2+(aq) solutions for an absorbance experiment. For the first standard, he uses
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Answer:

0.01 M

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The chemist is performing a serial dilution in order tyo obtain the calibration curve for the instrument.

First we must obtain the concentration of the solution in the 250ml flask from

C1V1 = C2V2

Where;

C1 = concentration of the stock solution

V1 = volume of the stock solution

C2 = concentration of the diluted solution

V2= volume of the diluted solution

2.61 × 10 = C2 × 250

C2 = 2.61 × 10/250

C2 = 0.1 M

Hence for solution in 100ml flask;

0.1 × 10 = C2 × 100

C2 = 0.1 × 10/100

C2 = 0.01 M

6 0
3 years ago
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