Question

Which shows the correct substitution of the values a, b, and c from the equation 1 = –2x + 3x2 + 1 into the quadratic formula? Quadratic formula:

Answer 1

$1=-2x+3x^2+1\\\\3x^2-2x+1-1=0\\\\3x^2-2x=0\\\\\boxed{a=3;\ b=-2;\ c=0}$

Answer 2

Answer:

$a=3$,  $b=-2$ and  $c=0$.

Step-by-step explanation:

We have been given an equation $1=-2x+3x^2+1$.

We know that a quadratic equation is in form $ax^2+bx+c$.

First of all, we need to convert our given equation in standard quadratic equation as shown:

$1-1=-2x+3x^2+1-1$

$0=-2x+3x^2$

$-2x+3x^2=0$

$3x^2-2x=0$

Upon comparing our equation with standard quadratic equation we can see that $a=3$,  $b=-2$ and  $c=0$.