All categories

4 years ago

I need help with this quickly!!

Mathematics

1 answer:

ExtremeBDS [4]4 years ago

5 0

Answer: 5√3

Step-by-step explanation: 4√3 + √3 = √3(4+1) = 5√3

You might be interested in

there are two food trucks for sale that would be perfect for your business. the blue food truck is in perfect condition, but 8,0

Gennadij [26K]

Answer:

blue truck-$82000 green truck-$90000

Step-by-step explanation:

x+8000=y

x+y=172000

7 0

3 years ago

Jason wanted to place all 540 marbles in the 3 newly bought boxes. If he wants to

kotegsom [21]

Answer:

The first box will have 90 marbles, the second 180 and the third 270.

Step-by-step explanation:

Division in a ratio of 1:2:3

1 + 2 + 3 = 6

The first box will have 1/6 of the marbles.

The second box will have 2/6 = 1/3 of the marbles

The third box will have 3/6 = 1/2 of the marbles.

First box:

One sixth, so:

(1/6)*540 = 540/6 = 90

Second box:

One third, so:

(1/3)*540 = 540/3 = 180

Third box:

One half, so:

(1/2)*540 = 540/2 = 270

The first box will have 90 marbles, the second 180 and the third 270.

7 0

3 years ago

Factor

solmaris [256]

The correct answer is C) (5m^50 - 11n^8) (5m^50 + 11n^8)

We can tell this because of the rule regarding factoring the difference of two perfect squares. When we have two squares being multiplied, we can use the following rule.

a^2 - b^2 = (a - b)(a + b)

In this case, or first term is 25m^100. So we can solve that by setting it equal to a^2.

a^2 = 25m^100 -----> take the square root of both sides

a = 5m^50

Then we can do the same for the b term.

b^2 = 121n^16 ----->take the square root of both sides

b = 11n^8

Now we can use both in the equation already given

(a - b)(a + b)

(5m^50 - 11n^16)(5m^50 + 11n^16)

8 0

3 years ago

What is the length of the diagonal of a cube of 4 inches

BartSMP [9]

First find the length of the diagonal of a square of side 4 inches:

d^2 = 4^2 + 4^2 = 2*4^2 = 32. Then the diagonal of the cube has length

sqrt( 32 + 4^2) = sqrt(32+16) = sqrt(48) = 4sqrt(3).

8 0

4 years ago

Caroline is considering two video game rental plans. Plan A can be modeled with the equation C = 2n, and Plan B can be modeled w

meriva

Options

A. Caroline rents exactly 7 games each month.

B. Caroline rents exactly 6 games each month.

C. Caroline rents 6 or more games each month.

D. Caroline rents from 1 to 5 games each month.

Answer:

D. Caroline rents from 1 to 5 games each month.

Step-by-step explanation:

Given

Plan A:

$C = 2n$

Plan B:

$C = n + 6$

Required

Which options justifies A over B

The solution to this question is option (d).

In option d, n = 1,2,3,4,5

When any of the values of n is substituted in plan A and B, respectively; the cost of plan A is cheaper than plan B.

This is not so, for other options (A - C)

To show:

Substitute 1 for n in A and B

Plan A:

$C = 2n$ $= 2 * 1 = 2$

Plan B:

$C = n + 6$ $= 1 + 6 = 7$

Substitute 5 for n in A and B

Plan A:

$C = 2n$ $= 2 * 5 = 10$

Plan B:

$C = n + 6$ $= 5 + 6 = 11$

8 0

3 years ago