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diamong [38]
3 years ago
14

A prototype shows if a product meets the required needs. True False

Physics
2 answers:
spayn [35]3 years ago
8 0

it is a true from me hahahahahahahahaa

Stolb23 [73]3 years ago
7 0

Answer: True

Explanation:

A prototype simulate the real and future product, the correctness of the design could be tested before it comes into production and if their is any error it could be detected

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Which word is not a good way to describe exercise?
Sveta_85 [38]
Exertion is not a good way to describe exercise but there is also alot more words to describe wrong ways for exercise
6 0
3 years ago
A force F with arrow applied to an object of mass m1 produces an acceleration of 3.10 m/s2. The same force applied to a second o
Bas_tet [7]

Answer:

(a) The value of the ratio m₁/m₂ is 0.581

(b)  the acceleration of the combined masses is 1.139 m/s²

Explanation:

Given;

The acceleration of force applied to M₁, a₁ = 3.10 m/s²

The same force applied to M₂ has acceleration, a₂ = 1.80 m/s²

Let this force = F

According Newton's second law of motion;

F = ma

(a) the value of the ratio m₁/m₂

since the applied force is same in both cases,  M₁a₁ = M₂a₂

\frac{m_1}{m_2} = \frac{a_2}{a_1} \\\\\frac{m_1}{m_2} = \frac{1.8}{3.1} \\\\\frac{m_1}{m_2} = 0.581

(b) the acceleration of m₁ and m₂ combined as one object under the action force F

F = ma

a = \frac{F}{M} \\\\a =  \frac{F}{m_1 + m_2} \\\\a = \frac{F}{0.581m_2 + m_2}\\\\a = \frac{F}{1.581m_2}

But, m_2 = \frac{F}{a_2} \\\\a = \frac{F}{1.581m_2} =  \frac{F*a_2}{1.581F} \\\\a = \frac{a_2}{1.581} \\\\a = \frac{1.8}{1.581} = 1.139 \ m/s^2

Therefore, the acceleration of the combined masses is 1.139 m/s²

5 0
3 years ago
What is the wavelength of a wave that has a frequency of 841 Hz if the speed of the wave is 457 m/s?
Dvinal [7]

Answer:

<h3>The answer is 0.54 m</h3>

Explanation:

The wavelength of a wave can be found by using the formula

\lambda =  \frac{c}{f}  \\

where

c is the velocity

f is the frequency

So we have

\lambda =  \frac{457}{841}  \\  = 0.543400713...

We have the final answer as

<h3>0.54 m</h3>

Hope this helps you

6 0
3 years ago
Pls answer ASAP!! What model of the atom was developed from Heisenberg's uncertainty principal?
blagie [28]

D. the electron cloud model

(process of elimination: chocolate chip model came way before, planetary and Bohr's are the same and were developed by Niels Bohr)

8 0
3 years ago
Read 2 more answers
If a spring is stretched 4m from its starting length when 20n of force is applied, then how much work (in joules) is done by the
lys-0071 [83]

ANSWER:

250 J

STEP-BY-STEP EXPLANATION:

F = 20N is required to stretch the spring by 4 meters

We know that the force is equal to:

F=k\cdot x

We solve for k (spring constant):

k=\frac{F}{x}=\frac{20}{4}=5\text{ N/m}

The work done in stretching the spring is given by the following equation (in this case the stretch is 10 meters:

\begin{gathered} W=\frac{1}{2}k\cdot x^2 \\ \text{ Replacing} \\ W=\frac{1}{2}\cdot5\cdot10^2 \\ W=250\text{ J} \end{gathered}

The work required is 250 joules.

5 0
1 year ago
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