Answer:
a) the rotational speed of the clay is 3.45 rad/s
b) the value of A in the equation of motion is 0.15 m
c) the value of ϕi is 90° or π/2 rad.
Explanation:
Given that;
Revolution per minute rpm = 33( 1/3) = 100/3
The frequency f = 100 / 3(60) = 0.55 Hz
a)
Rotational speed W = 2πf
we substitute
W = 2π × 0.55
W = 3.45 rad/s
Therefore, the rotational speed of the clay is 3.45 rad/s
b)
given equation; y(t)=Asin(ωt+ϕi)
given that radius = 0.15 m
y(t)=(0.2)sin(ωt+ϕi)
Therefore, the value of A in the equation of motion is 0.15 m
c)
since y(t) has the maximum value at t =0
so at t=0
y(0) = (0.15)sin(ω(0)+ϕi)
= 0.15sin(ϕi)
this will give maximum value when ϕi = 90°
so
y(0) = (0.15)sin(ω(0)+ϕi)
= 0.15sin(90°)
= 0.15
hence, the value of ϕi is 90° or π/2 rad.
Answer:
Subtract the kinetic energy at the bottom from the potential energy loss. The remainder becomes frictional heat.
Potential energy loss:
M g H = 21.7*9.81*3.5 = 745.1 J
Kinetic energy at bottom of slide:
= (1/2) M v^2 = 52.5 J
Atomic Number
or
Number of Protons
ΩΩΩΩΩΩΩΩΩΩ
That's two different things it depends on:
-- surface area exposed to the air
AND
-- vapor already present in the surrounding air.
Here's what I have in mind for an experiment to show those two dependencies:
-- a closed box with a wall down the middle, separating it into two closed sections;
-- a little round hole in the east outer wall, another one in the west outer wall,
and another one in the wall between the sections;
So that if you wanted to, you could carefully stick a soda straw straight into one side,
through one section, through the wall, through the other section, and out the other wall.
-- a tiny fan that blows air through a tube into the hole in one outer wall.
<u>Experiment A:</u>
-- Pour 1 ounce of water into a narrow dish, with a small surface area.
-- Set the dish in the second section of the box ... the one the air passes through
just before it leaves the box.
-- Start the fan.
-- Count the amount of time it takes for the 1 ounce of water to completely evaporate.
=============================
-- Pour 1 ounce of water into a wide dish, with a large surface area.
-- Set the dish in the second section of the box ... the one the air passes through
just before it leaves the box.
-- Start the fan.
-- Count the amount of time it takes for the 1 ounce of water to completely evaporate.
=============================
<span><em>Show that the 1 ounce of water evaporated faster </em>
<em>when it had more surface area.</em></span>
============================================
============================================
<u>Experiment B:</u>
-- Again, pour 1 ounce of water into the wide dish with the large surface area.
-- Again, set the dish in the second half of the box ... the one the air passes
through just before it leaves the box.
-- This time, place another wide dish full of water in the <em>first section </em>of the box,
so that the air has to pass over it before it gets through the wall to the wide dish
in the second section. Now, the air that's evaporating water from the dish in the
second section already has vapor in it before it does the job.
-- Start the fan.
-- Count the amount of time it takes for the 1 ounce of water to completely evaporate.
==========================================
<em>Show that it took longer to evaporate when the air </em>
<em>blowing over it was already loaded with vapor.</em>
==========================================
Answer: W = 11340J
Explanation:
Hey there! I will give the following steps, if you have any questions feel free to ask me in the comments below.
So this is the Formula: Power = Work / Time.
<u>Step 1:</u><em><u> Find the Formula</u></em>
P = W / T
<em><u>
</u></em>
<u>Step 2: </u><u><em>Make W the subject of the equation.</em></u>
W = PT
<u>Step 3:</u><u> </u><u><em>Given.</em></u>
P = 270 Watts, T = 42 seconds
<u>Step 4:</u><u><em> Substitute these values into equation 2
.</em></u>
W = 270(42)
<u>Step 5:</u><u> </u><u><em>Simplify.</em></u>
W = 11340J
The amount of work done was 11340.
~I hope I helped you! :)~
