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kiruha [24]
3 years ago
7

The density of lead is 30.2g/cm^3.what is the value in kilograms per meter cube?

Physics
1 answer:
V125BC [204]3 years ago
3 0
Answer:
11300 kgm3

Hope this helps
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7. What is the acceleration of the box?<br> a. 2.5 m/s2<br> b. 4 m/s2<br> c. 6 m/s2<br> d. 10 m/s2
faust18 [17]
This is your answer
b) 4m/s2
Here’s my work

6 0
3 years ago
Tidal Forces near a Black Hole. An astronaut inside a spacecraft, which protects her from harmful radiation, is orbiting a black
arlik [135]

Answer:

833.4801043*10^6N on ear that is closer to Black hole.

13.83803929*10^6N On ear that is farther from Black hole.

Explanation:

This problem can be solved as two masses that are at two different location from a bigger mass whose gravity affects both.

tension is an equal and opposite force that is exerted in response to applied force.

so on ear that is closer to black hole would have tension that is equal in magnitude and opposite in direction to gravitational force that ear experience due to the black hole at that location.

this true for ear that is further away from black hole as well.

(1) Force on ear that is closer to black hole.

                                                 F =\frac{m_{1}*m_{2}  }{r^2} G

                    m_{1}= 5*1.989*10^30kg is mass of Black hole.

                     m_{2}= 0.030kg is mass of ear that is close to black hole.

                    G = 6.679*10^-11m^3*kg^-1*s^-2

                     r = 120km-\frac{6}{100000} km=119.99994km=119999.94m

Note, we have subtracted because ear is closer to black hole.

plugging all this in formula gives.

                                      F = 833.4801043*10^6N

       That is tension of ear.

(2) Force on ear that is further from black hole.

                              F =\frac{m_{1}*m_{2}  }{r^2} G

                    m_{1}= 5*1.989*10^30kg is mass of Black hole.

                     m_{2}= 0.030kg is mass of ear that is close to black hole.

                    G = 6.679*10^-11m^3*kg^-1*s^-2

         this time r is further away from black hole so it would be.

                       r = 120km+\frac{6}{100000} km = 120000.06m

Plugging this all in we get

                          F = 13.83803929N

and that is tension on ear that is further from black hole.

Notice the tension difference, and order of magnitude of tension,it is enormous .

this astronaut is lethally close to black hole.

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3 years ago
A planet is orbiting a nearby star. Suppose that the star’s gravity increases over time. What effect will this increase most lik
zhenek [66]
The planet would stay in the same orbit but start revolving faster.
(Its year would get shorter.)
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What book did Galileo write that would influence sir issac newton
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The book Two New Sciences is the book that would later influence Sir Isaac Newton
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Ina vacuum, it is a constant value that does not depend on the observer.

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