<h2>~<u>Solution</u> :-</h2>
- Here, the <u>moment arm</u> is defined as follows;
The magnitude of two forces, which when acting at right angle produce resultant force of VlOkg and when acting at 60° produce resultant of Vl3 kg. These forces are D. gravitational force of attraction towards the centre of the earth. A sample of metal weighs 219 gms in air, 180 gms in water, 120 gms in an <em>unknown fluid</em>.

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Answer:
The charge on the dust particle is 
Explanation:
From the question we are told that
The length is 
The width is 
The charge is 
The mass suspended in mid-air is 
Generally the electric field on the carpet is mathematically represented as

Where
is the permittivity of free space with value 
substituting values


Generally the electric force keeping the dust particle on the air equal to the force of gravity acting on the particles

=> 
=> 
=> 
=> 
The magnitude of the magnetic force acting on the charge is 2.34×10⁻³ N.
<h3>What is magnetic force?</h3>
A magnetic force is the force that act in a magnetic field.
To calculate the magnetic force, we use the formula below.
Formula:
- F = qvB.........Equation 1
Where:
- F = magnetic force
- q = point charge
- v = Velocity of the the charge
- B = Field strength
From the question,
Given:
- q = 5.0×10⁻⁷ C
- v = 2.6×10⁵ m/s
- B = 1.8×10⁻² T
Substitute these values into equation 2
- F = (5.0×10⁻⁷)(2.6×10⁵)(1.8×10⁻²)
- F = 23.4×10⁻⁴
- F = 2.34×10⁻³ N
Hence, the magnitude of the magnetic force acting on the charge is 2.34×10⁻³ N.
Learn more about magnetic force here: brainly.com/question/2279150
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