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Sidana [21]
3 years ago
7

1 plus 1 equals to: Will only give stuff to terrypan

Mathematics
1 answer:
Anna007 [38]3 years ago
7 0

Answer:

2

Step-by-step explanation:

Thanks why do you know me

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Will give brainliest
Sonja [21]

The sum of the two <em>rational</em> equations is equal to (3 · n² + 5 · n - 10) / (3 · n³ - 6 · n²).

<h3>How to simplify the addition between two rational equations</h3>

In this question we must use <em>algebra</em> definitions and theorems to simplify the addition of two <em>rational</em> equations into a <em>single rational</em> equation. Now we proceed to show the procedure of solution in detail:

  1. (n + 5) / (n² + 3 · n - 10) + 5 / (3 · n²)      Given
  2. (n + 5) / [(n + 5) · (n - 2)] + 5 / (3 · n²)     x² - (r₁ + r₂) · x + r₁ · r₂ = (x - r₁) · (x - r₂)
  3. 1 / (n - 2) + 5 / (3 · n²)     Associative and modulative property / Existence of the multiplicative inverse
  4. [3 · n² + 5 · (n - 2)] / [3 · n² · (n - 2)]       Addition of fractions with different denominator
  5. (3 · n² + 5 · n - 10) / (3 · n³ - 6 · n²)       Distributive property / Power properties / Result

To learn more on rational equations: brainly.com/question/20850120

#SPJ1

4 0
2 years ago
8.7, 8.9, 9.0 is the answer
lapo4ka [179]

Answer: Wait Huh? Please Dm Me or Respond So i Can Help, I Promise (If i Can)

Step-by-step explanation:

6 0
3 years ago
Make a tree diagram and find each probability.
Dafna11 [192]

Answer:  a) probability that the game will be canceled= 45%

b) probability there will be a light drizzle and the game will not be canceled=20%

Step-by-step explanation:

Since we have given that

Probability of heavy fog is given by

P(F)=0.70

Probability of a light drizzle is given by

P(D)=0.30

Probability of getting canceled a softball game due to light drizzle is given by

P(C\mid D)=0.80

Probability of getting canceled a softball game due to heavy fog is given by

P(C\mid F)=0.30

a. Find the probability that the game will be canceled.

Probability of getting the game be cancelled is given by

P(C)=P(F)\times P(C\mid F)+P(D)\times P(C\mid D)\\\\P(C)=0.70\times 0.30+0.30\times 0.80\\\\P(C)=0.45\\\\P(C)=45\%

b. Find the probability there will be a light drizzle and the game will not be canceled.

Probability that there will be a light drizzle and the game will not be canceled is given by

P(C'\mid D)=1-P(C\mid D)\\\\P(C'\mid D)=1-0.80\\\\P(C'\mid D)=0.20\\\\P(C'\mid D)=20\%

Hence, a) probability that the game will be canceled= 45%

b) probability there will be a light drizzle and the game will not be canceled=20%

8 0
3 years ago
Here is the histogram of a data distribution. All class widths are 1.
JulsSmile [24]
Median is 6 so your answer is C
8 0
4 years ago
Negative plus positive=?
grin007 [14]
If you are adding a positive number to negative number. You are just bringing the negative number closer to zero, if not above zero.
Examples:
-1+1=0
-2+1=-1
-3+1=-2
-4+1=-3
7 0
3 years ago
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