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Ket [755]
3 years ago
14

A spring-powered dart gun is unstretched and has a spring constant 16.0 N/m. The spring is compressed by 8.0 cm and a 5.0 gram p

rojectile is placed in the gun. The kinetic energy of the projectile when it is shot from the gun is
Physics
1 answer:
stepladder [879]3 years ago
4 0

Answer:

Explanation:

Given that,

Spring constant = 16N/m

Extension of spring

x = 8cm = 0.08m

Mass

m = 5g =5/1000 = 0.005 kg

The ball will leave with a speed that makes its kinetic energy equal to the potential energy of the compressed spring.

So, Using conservation of energy

Energy in spring is converted to kinectic energy

So, Ux = K.E

Ux = ½ kx²

Then,

Ux = ½ × 16 × 0.08m²

Ux = 0.64 J

Since, K.E = Ux

K.E = 0.64 J

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g Drop the object again and carefully observe its motion after it hits the ground (it should bounce). (Consider only the first b
Anestetic [448]

Answer:

a) quantity to be measured is the height to which the body rises

b) weighing the body , rule or fixed tape measure

c)   Em₁ = m g h

d) deformation of the body or it is transformed into heat during the crash

Explanation:

In this exercise of falling and rebounding a body, we must know the speed of the body when it reaches the ground, which can be calculated using the conservation of energy, since the height where it was released is known.

a) What quantities must you know to calculate the energy after the bounce?

The quantity to be measured is the height to which the body rises, we assume negligible air resistance.

So let's use the conservation of energy

starting point. Soil

          Em₀ = K = ½ m v²

final point. Higher

          Em_f = U = mg h

         Em₀ = Em_f

         Em₀ = m g h₀

b) to have the measurements, we begin by weighing the body and calculating its mass, the height was measured with a rule or fixed tape measure and seeing how far the body rises.

c) We use conservation of energy

starting point. Soil

          Em₁ = K = ½ m v²

final point. Higher

          Em_f = U = mg h

         Em₁ = Em_f

         Em₁ = m g h

d) to determine if the energy is conserved, the arrival energy and the output energy must be compared.

There are two possibilities.

* that have been equal therefore energy is conserved

* that have been different (most likely) therefore the energy of the rebound is less than the initial energy, it cannot be stored in the possible deformation of the body or it is transformed into heat during the crash

7 0
3 years ago
How much energy does a pair of 800W hair straighteners transfer every second
Natali5045456 [20]
800 J since watts is a measurement of joules per second
3 0
4 years ago
A girl weighing 600 N steps on a bathroom scale that contains a stiff spring. In equilibrium, the spring is compressed 1.0 cm un
8_murik_8 [283]

Answer:

The spring constant is 60,000 N

The total work done on it during the compression is 3 J

Explanation:

Given;

weight of the girl, W = 600 N

compression of the spring, x = 1 cm = 0.01 m

To determine the spring constant, we apply hook's law;

F = kx

where;

F is applied force or weight on the spring

k is the spring constant

x is the compression of the spring

k = F / x

k = 600 / 0.01

k = 60,000 N

The total work done on the spring = elastic potential energy of the spring, U;

U = ¹/₂kx²

U = ¹/₂(60000)(0.01)²

U = 3 J

Thus, the total work done on it during the compression is 3 J

3 0
3 years ago
The behavior of gas are dependent on all of the factors
Slav-nsk [51]

Answer:

Explanation:

Pressure (P): the force exerted by gas molecules as they strike a given surface.

Volume (V): the space occupied by gas molecules.

Temperature (T): A measure of how fast gas molecules move (kinetic energy).

Amount (n): Amount in moles of gas molecules.

7 0
3 years ago
Oxygen and hydrogen are kept under the same temperature and pressure. Oxygen molecule is 16 times more massive than hydrogen one
olya-2409 [2.1K]

Answer:

The average speed of molecule of oxygen is one-fourth of the speed of the hydrogen molecule.

Explanation:

The kinetic energy of gas molecule is given by following equation:

K.E = \frac{3}{2} KT

Since the temperature (T) is constant for both molecules. Therefore, there kinetic energies will also be the same. Therefore,

K.E_{O_2} = K.E_{H_2}\\\frac{1}{2}m_{O_2}v_{O_2}^2 =  \frac{1}{2}m_{H_2}v_{H_2}^2 \\\\but,\\\\m_{O_2} = 16m_{H_2}\\\\therefore,\\16 m_{H_2}v_{O_2}^2 = m_{H_2}v_{H_2}^2\\\\\\taking square root on both sides, we get:\\4v_{O_2} = v_{H_2}\\\\v_{O_2} = \frac{v_{H_2}}{4}

<u>The average speed of molecule of oxygen is one-fourth of the speed of the hydrogen molecule.</u>

7 0
3 years ago
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