The solution for the problem is:
Wavelength = Planck’s constant/(mass*velocity)
Planck’s constant= 6.63*10^-34 with units of J-s or kg-m^2/s^2-s
mass = 149g = 0.149 kg
velocity = 95.4.mi/1hr(1609.3m/1mi)(1hr/3600sec) = 42.65m/s
h/mv = 6.63*10^-34 kg-m^2/s^2-s/(42.65m/s*0.149kg)
wavelength = 1.04 *10^-34 m
Answer:
(a) 0.075
(b)20.1 mA
(c) 2.412 W
Explanation:
Vs = 9 V, is = 268 mA = 0.268 A
Vp = 120 V
(a) Let the number of turns in primary coil is Np and the number of turns in secondary coil of the transformer is Ns.
Ns / np = Vs / Vp
Ns / Np = 9 / 120
Ns / Np = 3 : 40 = 0.075
(b) Let the current drawn from the wall socket is ip.
Ns/ Np = ip / is
0.075 = ip / 0.268
ip = 0.0201 A = 20.1 mA
(c) Power delivered by the socket = Vp x ip = 120 x 0.0201 = 2.412 W
Power sent to the batteries = Vs x is = 9 x 0.268 = 2.412 W
Since <span>volume of each cube is 1 cm^3
Then we can get the </span>volume of 1 mole of cubes, which is
The edge
And the new adge that we are looking for:
=
So, the final soution for the edge length of cube is 844km.
Do hope it helps!
Regards.
We are given with
M = mass of planet
R = radius of circular trajectory of the satellite
ms = mass of the station
mm = mass of the meteorite
ms = 10 mm
R/2 = new orbit distance
The speed of the meteorite can be solved using the law of conservation of momentum
ms vs + mm vm = (ms + mm) v
Since the new orbit distance is half the original
v = 2 vs
Substitute and solve for vs
