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Mademuasel [1]
3 years ago
5

A musician playing a string instrument may use a finger to push a string tightly against the fingerboard of her instrument, thus

shortening the length of the string. This causes the fundamental frequency to (a) increase, (b) decrease, (c) not change.
Physics
1 answer:
Thepotemich [5.8K]3 years ago
7 0

Answer:

a) increase

Explanation:

The frequency of sound produced due to vibration of a string is governed by the following formula  

n = 1/2L√T/m ;

L is length of the string  in vibration, T is tension in the  string  and m is mass of string per unit length.

So frequency is inversely proportional to length of the string. Hence shortning of length of string increases the frequency of vibration.

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A brick is dropped (zero initial speed) from the roof of a building. The brick strikes the ground in 1.90 s. You may ignore air
Gekata [30.6K]

Answer: Height of building = 17.69m, velocity of brick = 18.6m/s

Explanation: From the question, the body has a zero initial speed, thus initial velocity (u) all through the motion is zero.

By ignoring air resistance makes it a free fall motion thus making it to accelerate constantly with a value of a = 9.8m/s^{2}.

Time taken to fall = 1.90s

a)

thus the height of the building is calculated using the formulae below

H = ut + \frac{1}{2} gt^{2}

but u = 0 , hence

H = \frac{1}{2} gt^{2}

H = \frac{1}{2} *9.8* 1.9^{2} \\\\H = 17.69m

b)

to get the value of velocity (v) as the brick hits the ground, we use the formulae below

v^{2} = u^{2} + 2aH

but u= 0, hence

v^{2} = 2gH\\

v^{2} = 2 * 9.8 * 17.69\\v = \sqrt{2 *9.8* 17.69} \\v = 18.62m/s

 

find the attachment in this answer for the accleration- time graph, velocity- time graph and distance time graph

8 0
4 years ago
A makeshift sign hangs by a wire that is extended over an ideal pulley and is wrapped around a large potted plant on the
ella [17]

Answer:I know the answer for B cus I’m doing the same problem. For B, you would only take the coefficient of friction given and then multiply it by the Normal Force, which in this case is the same as the Gravitational Force.

Explanation:

4 0
4 years ago
Calculate the angular velocity of a clocks second hand, its minute hand, and its hour hand. State in Rad/s. What is its angular
fenix001 [56]

Second hand:

1 rev per minute = (2π radians/minute) x (1 min/60sec) = π/30 rad/sec

Minute hand:

1 rev per hour = (2π radians/hour) x (1 hr/3600 sec) = π/1800 rad/sec

Hour hand:

1 rev per 12 hours = (2π rad/12 hr) x (1 hr/3600 sec) = π/21,600 rad/sec

As long as the clock is in good working order, and the hands are turning steadily at their normal rate, there is no angular acceleration.

8 0
3 years ago
Your abrasive wheel guards should follow which of the standards below: A. All of the answers B. Cover the spindle end, nut, and
Elden [556K]
The answer Is [A] All of the answers.
7 0
3 years ago
Read 2 more answers
A moving walkway at the airport moves a 120Kg person 35m in 150s. How much power did this require?
Alexxx [7]

The amount of power required to move the 120 Kg person to a distance of 35 m in 150 s is 274.4 W

<h3>How to determin the power</h3>

Power is simply defined as the rate at which work is done. It can be expressed mathematically as

Power (P) = work (W) / time (t)

But

Work = force (F) × distance (d)

Therefore,

P = Fd / t

With the above formula, we can obtain the power as follow:

  • Mass (m) = 120 Kg
  • Distance (d) = 35 m
  • Time (t) = 150 s
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Force (F) = mg = 120 × 9.8 = 1176 N
  • Power (P) = ?

P = Fd / t

P = (1176 × 35) / 150

P = 41160 / 150

P = 274.4 W

Thus, the power is 274.4 W

Learn more about power:

brainly.com/question/20353916

#SPJ1

6 0
1 year ago
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