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lbvjy [14]
3 years ago
15

Determine the minimum amount of energy (in MeV) needed to remove a neutron from a 88Sr nucleus. (For all masses, keep six places

beyond the decimal point when performing your calculations. Then round your final answer to at least three significant figures.)
Physics
1 answer:
Sindrei [870]3 years ago
6 0

Answer:

  11.106 Mev.

Explanation:

Sr⁸⁸         →        Sr ⁸⁷      +       ₀n¹

87.905612       86.908877       1.008664   ( atomic masses in amu )

mass defect = ( 86.908877 + 1.008664) - 87.905612 = .011929 amu.

Equivalent energy in MeV = .011929 x 931 = 11.106 MeV

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The time T in seconds for a pendulum of length L feet to make one swing is given by Upper T=2\pi \sqrt((L)/(36)). How long is a
Andreyy89

Answer:

3.6ft

Explanation:

Using= 2*π*sqrt(L/32)

To solve for L, first move 2*n over:

T/(2*π) = sqrt(L/32)

Next,eliminate the square root by squaring both sides

(T/(2*π))2 = L/32

or

T2/(4π2) = L/32

Lastly, multiply both sides by 32 to yield:

32T2/(4π2) = L

and simplify:

8T²/π²= L

Hence, L(T) = 8T²/π²

But T = 2.1

Pi= 3.14

8(2.1)²/3.14²

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3 years ago
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The time constants 30 seconds and the can form an RC Charging circuit.

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If R = 150 kΩ = 150000Ω

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<u>= 30 seconds.</u>

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3 0
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Answer:

This is very true

Explanation:

The force from impact can easily change it to expanse in a different direction.

I hope this helped you very much :)

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