A CPU has 32 KB cache, 2-way set associative, 16-byte block size. How many bits are required to use index each set in this cache
?
1 answer:
Answer:
10 bits
Explanation:
Cache size = 32 KB
We were also given that it is 2 way set associative
Block size = 16 bytes = 2^4 = 4 bits for offset
Number of blocks = cache size / block size = (32*2^10) / 16
=2^11
Hence, index = number of blocks / 2 (since 2 way associative)
=(2^11)/2 = 2^10 = 10 bits for index
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