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MA_775_DIABLO [31]
3 years ago
6

A CPU has 32 KB cache, 2-way set associative, 16-byte block size. How many bits are required to use index each set in this cache

?
Computers and Technology
1 answer:
LenKa [72]3 years ago
7 0

Answer:

10 bits

Explanation:

Cache size = 32 KB

We were also given that it is 2 way set associative

Block size = 16 bytes = 2^4 = 4 bits for offset

Number of blocks = cache size / block size = (32*2^10) / 16

=2^11

Hence, index = number of blocks / 2 (since 2 way associative)

=(2^11)/2 = 2^10 = 10 bits for index

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7 0
2 years ago
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icang [17]

Answer:

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Explanation:

When the same variable name is repeated in the parameter set and the method body, it will result in a syntax error. This is because the variable in the parameter has a local scope within the method body. Now if we declare another variable with the same name in the method body, it will result in redefinition of the variable and violate the uniqueness principle of variable names in the method code. This will give rise to syntax error.

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4 years ago
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julsineya [31]
The answer would be (DOCSIS). :)

Have a blessed day and hope this helps!
7 0
3 years ago
You have informed your users that you need to bring the machine down at the end of the day to perform routine maintenance. Howev
PSYCHO15rus [73]

Answer:

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This is your perfect answer

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