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Artist 52 [7]
3 years ago
10

A basketball team lost 1/5 of their games this season. If the team won 12 games, how many games did they play?

Mathematics
1 answer:
expeople1 [14]3 years ago
5 0
They played 15 games total
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44.5 + g = 50 answer
soldi70 [24.7K]

Answer:

44.5 + g = 50 \\ g = 50 - 44.5 \\ g = 5.5

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3 years ago
Simplify the following expression.
AlekseyPX

Answer:

The answer is cosx cot²x ⇒ the first answer

Step-by-step explanation:

∵ cot²x = cos²x/sin²x

∵ secx = 1/cosx

∴ cot²x secx - cosx = (cos²x/sin²x)(1/cosx) - cosx

  = (cosx/sin²x) - cosx

Take cosx as a common factor

∴ cosx[(1/sin²x) - 1] ⇒ use L.C.M

∴  cosx[1-sin²x/sin²x]

∵ 1 - sin²x = cos²x

∴ cosx(cos²x/sin²x) = cosx cot²x

6 0
3 years ago
Using this distribution, find the probability
kaheart [24]

Answer:

P = 0.3

Step-by-step explanation:

Here, we are to use the probability distribution in the table to calculate the probability that a children has 4 or more shoes in his or her closet

When we say 4 or more, what we mean by this is that the teenager has 4 shoes or 5 shoes

In probability expressions, when we use the term ‘or’ we are simply talking about adding the terms involved

So what we can do here is to add the probability that the teenager has 4 shoes to the probability that the teenager has five shoes

From the table that would be; 0.1 + 0.2 = 0.3

6 0
4 years ago
What is the discount if the price is 55 and the sale price is 46.75
SVEN [57.7K]
Starting: 46.75
After 55% discount: 21.04
Total: $21.04
5 0
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Consider the functions below. f(x, y, z) = x i − z j + y k r(t) = 4t i + 6t j − t2 k (a) evaluate the line integral c f · dr, wh
fredd [130]

With

\vec r(t)=4t\,\vec\imath+6t\,\vec\jmath-t^2\,\vec k

we have

\mathrm d\vec r=(4\,\vec\imath+6\,\vec\jmath-2t\,\vec k)\,\mathrm dt

The vector field evaluated over this parameterization is

\vec f(x,y,z)=\vec f(x(t),y(t),z(t))=4t\,\vec\imath+t^2\,\vec\jmath+6t\,\vec k

so the line integral is

\displaystyle\int_{-1}^1(4t\,\vec\imath+t^2\,\vec\jmath+6t\,\vec k)\cdot(4\,\vec\imath+6\,\vec\jmath-2t\,\vec k)\,\mathrm dt

=\displaystyle\int_{-1}^1(16t+6t^2-12t^2)\,\mathrm dt=-4

6 0
3 years ago
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