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3 years ago

A delivery truck travels 55 miles per hour. How many feet per hour is Mr. Jones driving?

Mathematics

1 answer:

Irina-Kira [14]3 years ago

3 0

Answer:

A delivery truck, Mr. Jones drives 290400 feet per hour.

Step-by-step explanation:

To Determine:

How many feet per hour is Mr. Jones driving?

Solution Steps:

A delivery truck travels 55 miles per hour.

As we know that

Total number of feet in one mile = 5,280

Total number of feet in 55 miles = 5,280 × 55 = 290400

Thus

A delivery truck travels 290400 feet per hour.

Therefore, a delivery truck, Mr. Jones drives 290400 feet per hour.

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DOES ANYONE KNOW THE ANSWER ???? Please I can’t fail this test !

Zigmanuir [339]

Answer:

The last option

Step-by-step explanation:

You take the middle 2 numbers, add them up, and divide by 2.

6 0

2 years ago

Find the roots of the equation<br> x ^ 2 + 3x-8 ^ -14 = 0 with three precision digits

scoray [572]

Answer:

Step-by-step explanation:

Given quadratic equation:

$x^{2} + 3x - 8^{- 14} = 0$

The solution of the given quadratic eqn is given by using Sri Dharacharya formula:

$x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}$

The above solution is for the quadratic equation of the form:

$ax^{2} + bx + c = 0$

$x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}$

From the given eqn

a = 1

b = 3

c = $- 8^{- 14}$

Now, using the above values in the formula mentioned above:

$x_{1, 1'} = \frac{- 3 \pm \sqrt{3^{2} - 4(1)(- 8^{- 14})}}{2(1)}$

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})})$

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})} - 3)$

Now, Rationalizing the above eqn:

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(- 8^{- 14})} - 3)\times (\frac{\sqrt{9 - 4(- 8^{- 14})} + 3}{\sqrt{9 - 4(- 8^{- 14})} + 3}$

$x_{1, 1'} = \frac{1}{2}.\frac{(\pm {9 - 4(- 8^{- 14})^{2}} - 3^{2})}{\sqrt{9 - 4(- 8^{- 14})} + 3}$

Solving the above eqn:

$x_{1, 1'} = \frac{2\times 8^{- 14}}{\sqrt{9 + 4\times 8^{-14}} + 3}$

Solving with the help of caculator:

$x_{1, 1'} = \frac{2\times 2.27\times 10^{- 14}}{\sqrt{9 + 42.27\times 10^{- 14}} + 3}$

The precise value upto three decimal places comes out to be:

$x_{1, 1'} = 0.758\times 10^{- 14}$

5 0

3 years ago

The quality control team of a company checked 800 digital cameras for defects. The team found that 20 cameras had lens defects,

dmitriy555 [2]

Answer:

0.025

Step-by-step explanation:

-This is a conditional probability problem.

-Let L denote lens defect and C charging defect.

#We first calculate the probability of a camera having a lens defect;

$P(lens)=\frac{Lens}{Total}\\\\=\frac{20}{800}\\\\=0.025$

#Calculate the probability of a camera having a charging defect:

$P(Charging)=\frac{Charging}{Total}\\\\=\frac{25}{800}\\\\=0.03125$

The the probability that a camera has a lens defect given that it has a charging defect is calculated as:

$P(L|C)=\frac{P(C)P(L)}{P(C)}\\\\=\frac{0.025\times 0.03125}{0.03125}\\\\=0.025$

Hence, the probability that a camera has a lens defect given that it has a charging defect is 0.025

6 0

2 years ago

One gallon of paint covers 400 square feet of surface area. A typical spherical water tower holds 66,840.28 cubic feet of water.

enot [183]

Answer: There will enough to paint the outside of a typical spherical water tower.

Step-by-step explanation:

1. Solve for the radius r from the formula for calculate the volume of a sphere. as following:

$V=\frac{4}{3}r^{3}\pi\\\frac{3V}{4\pi}=r^{3}\\r=\sqrt[3]{\frac{3V}{4\pi}}$

2. Substitute values:

$r=\sqrt[3]{\frac{3(66,840.28ft^{3})}{4\pi}}=25.17ft$

3. Substitute the value of the radius into the equation fo calculate the surface area of a sphere, then you obtain that the surface area of a typical spherical water tower is:

$SA=4r^{2}\pi\\SA=4(25.17ft)^{2} \pi\\SA=7,964.95ft^{2}$

3. If a city has 25 gallons of paint available and one gallon of paint covers 400 square feet of surface area, you must multiply 25 by 400 square feet to know if there will be enough to paint the outside of a typical spherical water tower.

$25*400ft^{2}=10,000ft^{2}$

As you can see, there will enough to paint the outside of a typical spherical water tower.

7 0

3 years ago

A random sample of 11 university students produced the following data, where x is the minutes spent studying per day, and y is t

SIZIF [17.4K]

Answer:

16.373,16.4

Step-by-step explanation:

Given that a random sample of 11 university students produced the following data, where x is the minutes spent studying per day, and y is the first exam score (out of a maximum of 100 points).

x y

11 39

13 55

14 43

17 46

19 69

22 75

24 77

25 78

28 77

31 93

34 92 Observations 11

ANOVA

df SS MS F Significance F

Regression 1 3214.095153 3214.095153 69.46052448 1.59367E-05

Residual 9 416.4503017 46.27225574

Total 10 3630.545455

Coefficients Standard Error t Stat P-value Lower 95% Upper 95% Lower 95.0% Upper 95.0%

Intercept 16.37281677 6.48384963 2.525169105 0.0324919 1.705329914 31.04030362 1.705329914 31.04030362

x 2.369323595 0.28428592 8.33429808 1.59367E-05 1.726224167 3.012423023 1.726224167 3.012423023

We get regression line as y =2.369x+16.373

a) value of intercept = 16.373

b) 16.4

8 0

2 years ago