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marissa [1.9K]
3 years ago
15

Two cars are traveling at the same speed of 22 m/s on a curve that has a radius of 114 m. Car A has a mass of 1040 kg, and car B

has a mass of 1610 kg. Find (a) the magnitude of the centripetal acceleration and (b) the magnitude of the centripetal force for Car A, (c) the magnitude of the centripetal acceleration and (d) the magnitude of the centripetal force for Car B.
Physics
1 answer:
natka813 [3]3 years ago
5 0

Answer:

(a) 4.25 m/s^2

(b) 4420 N

(c) 4.25 m/s^2

(d) 6842.5 N

Explanation:

(a) Centripetal acceleration of car A, a_c, is given as;

a_c = \frac{v^2}{r}

where v = velocity of car

r = radius of curve

a_c = \frac{22^2}{114}\\ \\\\a_c = 4.25 m/s^2

(b) Centripetal force of car A is given as:

F_A = m_A*a_c = m_A*\frac{v^2}{r}

F_A = 1040 * 4.25 = \\\\\\F_A = 4420 N

(c) Since car A and car B have the same speed, they have the same centripetal acceleration (a_c = 4.25 m/s^2)

(d) Centripetal force of car A is given as:

F_B = m_B*a_c = m_B*\frac{v^2}{r}

F_A = 1610 * 4.25 = \\\\\\F_A = 6842.5N

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A van is traveling with an initial velocity of 12 m/s. The driver takes a time of 45 seconds to speed up to a velocity of 20 m/s
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  • Initial velocity=u=12m/s
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\\ \rm\hookrightarrow Acceleration=\dfrac{v-u}{t}

\\ \rm\hookrightarrow Acceleration=\dfrac{20-12}{45}

\\ \rm\hookrightarrow Acceleration=\dfrac{8}{45}

\\ \rm\hookrightarrow Acceleration=0.1m/s^2

Now

  • Distance=s

\\ \rm\hookrightarrow v^2-u^2=2as

\\ \rm\hookrightarrow (20)^2-12^2=2(0.1)s

\\ \rm\hookrightarrow 400-144=0.2s

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Explanation:

When the package is thrown out, momentum is conserved. The total momentum after is the same as the total momentum before, which is 0, since the boat was initially at rest.

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where m_c = 24.6 kg, m_b = 39 kg, m_p = 5.8 kg are the mass of the child, the boat and the package, respectively. , v_p = 10m/s, v_b are the velocity of the package and the boat after throwing.

(24.6 + 39)v_b + 5.8*10 = 0

63.6v_b + 58 = 0

v_b = -58/63.6 = -0.912 m/s

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