Answer: a) Mr = 2.4×10^-4kg/s
V = 34.42m/a
b) E = 173J
Ø = 2693.1J
c) Er = 0.64J/s
Explanation: Please find the attached file for the solution
Answer:571.09 kJ
Explanation:
Given
Temperature of cooling water from engine exit
After Passing through the radiator its temperature decreases to 
specific heat of water
Volume of water 
density of water 
Thus mass of water
Heat transferred to the surrounding is equal to heat absorbed by cooling water




Explanation:
The answer is in the pic above
I think there might be less pollution
It is called an ion (positive or negative ion)